Java 根据对象字段对 ArrayList 进行排序
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Sort an ArrayList based on an object field
提问by devnull
Possible Duplicate:
Sorting an ArrayList of Contacts
可能的重复：
对联系人的 ArrayList 进行排序
I am storing DataNodeobjects in an ArrayList. The DataNodeclass has an integer field called degree.
I want to retrieve DataNodeobjects from nodeList in the increasing order of degree. How can I do it.
我将DataNode对象存储在ArrayList. 该DataNode班有一个名为整型字段degree。我想找回DataNode在递增的顺序从节点列表对象degree。我该怎么做。
List<DataNode> nodeList = new ArrayList<DataNode>();
采纳答案by blitzkriegz
Modify the DataNode class so that it implements Comparable interface.
修改 DataNode 类，使其实现 Comparable 接口。
public int compareTo(DataNode o)
{
return(degree - o.degree);
}
then just use
然后只需使用
Collections.sort(nodeList);
回答by Mark Elliot
Use a custom comparator:
使用自定义比较器：
Collections.sort(nodeList, new Comparator<DataNode>(){
public int compare(DataNode o1, DataNode o2){
if(o1.degree == o2.degree)
return 0;
return o1.degree < o2.degree ? -1 : 1;
}
});
回答by camickr
You can use the Bean Comparatorto sort on any property in your custom class.
您可以使用Bean Comparator对自定义类中的任何属性进行排序。
