Javascript 数字和破折号的正则表达式

Regular Expression for number and dash

提问by hungneox

Currently I write the regex like this: /^([\d+]*-)+([\d]*-)+([\d])*$/

目前我这样写正则表达式： /^([\d+]*-)+([\d]*-)+([\d])*$/

I want the result follow this pattern 00-123-456-789or 00123456789(dash between number group or no dash at all)

我希望结果遵循这种模式00-123-456-789或00123456789（数字组之间的破折号或根本没有破折号）

• not 00-123--457-789
• or -00-123-456-789-
• or -00123456789-
• or 00-123-456-789-

• 不是 00-123--457-789
• 或者 -00-123-456-789-
• 或者 -00123456789-
• 或者 00-123-456-789-

How can I modify the regex to matches the pattern above?

如何修改正则表达式以匹配上面的模式？

回答by jfriend00

If your question needs the specific segment lengths you specify in your examples, you can use this:

如果您的问题需要您在示例中指定的特定段长度，您可以使用：

/^\d{2}-?\d{3}-?\d{3}-?\d{3}$/

This will accept 00-123-456-789, but will allow for any dashes to be missing. If you want to allow only for all dashes or no dashes, then you could use this:

这将接受00-123-456-789，但将允许丢失任何破折号。如果你只想允许所有破折号或没有破折号，那么你可以使用这个：

/^\d{2}-\d{3}-\d{3}-\d{3}$|^\d{11}$/

which will accept only 00-123-456-789or 00123456789, but not allow only some dashes to be missing.

它将只接受00-123-456-789or 00123456789，但不允许只丢失一些破折号。

Or, if you meant that you could have any number of digits and any number of single dashes between them, then you could use this:

或者，如果你的意思是你可以有任意数量的数字和任意数量的单破折号，那么你可以使用这个：

/^\d+(-\d+)*$/

回答by Phil

Try something like this

尝试这样的事情

/^(\d+-?)+\d+$/

回答by MetaEd

If I understand you correctly, you wish your regex to stand for strings which consist of a number group followed (optionally) by additional number groups with a -separator.

如果我理解正确，您希望您的正则表达式代表由数字组组成的字符串，后跟（可选）带有-分隔符的附加数字组。

\d+      # represents a number group
(-\d+)*  # represents 0 or more additional number groups beginning with "-"

So, together with the necessary beginning and end of line assertions, together we have:

所以，加上必要的行首和行尾断言，我们有：

^\d+(-\d+)*$

回答by vkuberan

The following answer will be used to match

以下答案将用于匹配

00-123-456-789 or 00 123 456 789

00-123-456-789 或 00 123 456 789

/^[\d]{2}[-\s]?[\d]{3}[-\s]?[\d]{3}[-\s]?[\d]{3}$/

/^[\d]{2}[-\s]?[\d]{3}[-\s]?[\d]{3}[-\s]?[\d]{3}$/

If you want only to match hyphen(-) or without hyphen(-)

如果您只想匹配连字符 (-) 或不匹配连字符 (-)

Then it will do

然后它会做

/^[\d]{2}[-]?[\d]{3}[-]?[\d]{3}[-]?[\d]{3}$/

/^[\d]{2}[-]?[\d]{3}[-]?[\d]{3}[-]?[\d]{3}$/

回答by Godwin

If you only want to accept ##-###-###-### or ###########, then what you need is something like:

如果您只想接受##-###-###-### 或###########，那么您需要的是：

/^(([\d+]{2}\-)([\d]{3}\-){2}([\d]{3})|[\d]{11})$/

回答by Alessandro Vendruscolo

From what have you provided us, this regex ^-?(\d+-?)+$matches this

根据您提供给我们的信息，此正则表达式^-?(\d+-?)+$与此匹配

-00-123-456-789-
-00123456789-
00-123-456-789-
00123456789

but doesn't match this:

但与此不符：

00-123--457-789

Breakdown:

分解：

• the string can start with a dash (^-?)
• it has some digits followed by an optional dash (\d+-?)
• the last group can be repeated one or more times ((\d+-?)+)
• the string ends ($)

• 字符串可以以破折号 ( ^-?)开头
• 它有一些数字后跟可选的破折号 ( \d+-?)
• 最后一组可以重复一次或多次 ( (\d+-?)+)
• 字符串结束 ( $)

回答by techno

@godwin: since I can't add a comment to your post and no one else seems to have responded, let me address at least one issue. At the beginning you have

@godwin：由于我无法在您的帖子中添加评论，而且似乎没有其他人回复，让我至少解决一个问题。一开始你有

[\d+]{2}\-

\d+will match one or more digits and you're asking for it to be repeated twice, so the whole segment will match 123456789-:

\d+将匹配一位或多位数字，并且您要求将其重复两次，因此整个段将匹配123456789-：

• [\d+]= 12345678(greedy matching)
• [\d+]= 9
• \-= -

• [\d+]= 12345678（贪婪匹配）
• [\d+]= 9
• \-= -

You also probably didn't need to escape the dash because it's not inside a group block "[]".

您也可能不需要逃避破折号，因为它不在组块内"[]"。