bash 获取执行脚本的目录名称
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Get the name of the directory where a script is executed
提问by rodnower
I have some script, that uses files in directories around it. It uses
我有一些脚本，它使用它周围目录中的文件。它用
dirname if [ -L $(dirname $(realpath python2.6 -c "import os,sys; print os.path.realpath(sys.argv[1])" "dirname $(readlink -f readlink -f `which java`
)
"
))
] ; then
ME=$(readlink dirname $(readlink -f `which java`)
)
else
ME=##代码##
fi
DIR=$(dirname $ME)
command. It should work from any directory where I run this script, but when I run a symbolic link that points to that script I get the path of symbolic link. So I get the output of dirname rather than the path of the script itself.
命令。它应该在我运行这个脚本的任何目录中工作，但是当我运行一个指向该脚本的符号链接时，我得到了符号链接的路径。所以我得到的是 dirname 的输出而不是脚本本身的路径。
Any one know a way to get the path of where the script is run?
任何人都知道一种获取脚本运行路径的方法吗？
采纳答案by jmz
Get the real path to your script
获取脚本的真实路径
##代码##回答by knittl
if you have realpathinstalled:
如果您已realpath安装：
回答by loevborg
Unless I misunderstand you, the problem should be the same as the one in: How do you normalize a file path in Bash?
除非我误解你的意思，否则问题应该与：如何在 Bash 中规范化文件路径中的问题相同？
An option not mentioned there is the following python one-liner:
一个没有提到的选项是以下 python 单行：
##代码##Finally, remember to use double quotes around "$0".
最后，请记住在“$0”周围使用双引号。
回答by Alexandre Santos
A simpler solution:
一个更简单的解决方案：
##代码##Tested with on Ubuntu 14.04:
which javareturns /usr/bin/java, which is a symbolic link.
在 Ubuntu 14.04 上测试：
which java返回/usr/bin/java，这是一个符号链接。
Returns /usr/lib/jvm/java-8-oracle/jre/bin/java
退货 /usr/lib/jvm/java-8-oracle/jre/bin/java
Finally,
最后，
##代码##Returns /usr/lib/jvm/java-8-oracle/jre/bin, which is the folder under which "java" is located.
返回/usr/lib/jvm/java-8-oracle/jre/bin，即“java”所在的文件夹。
