ios 如何在 Swift 中解析来自 Alamofire API 的 JSON 响应？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/26114831/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
How to parse JSON response from Alamofire API in Swift?
提问by Developer
Following code I have written and I am getting response in JSON also but the type of JSON is "AnyObject" and I am not able to convert that into Array so that I can use that.
按照我编写的代码，我也收到了 JSON 响应，但 JSON 的类型是“AnyObject”，我无法将其转换为 Array 以便我可以使用它。
Alamofire.request(.POST, "MY URL", parameters:parameters, encoding: .JSON) .responseJSON
{
(request, response, JSON, error) in
println(JSON?)
}
回答by Joseph Geraghty
The answer for Swift 2.0 Alamofire 3.0 should actually look more like this:
Swift 2.0 Alamofire 3.0 的答案实际上应该更像这样：
Alamofire.request(.POST, url, parameters: parameters, encoding:.JSON).responseJSON
{ response in switch response.result {
case .Success(let JSON):
print("Success with JSON: \(JSON)")
let response = JSON as! NSDictionary
//example if there is an id
let userId = response.objectForKey("id")!
case .Failure(let error):
print("Request failed with error: \(error)")
}
}
UPDATE for Alamofire 4.0 and Swift 3.0 :
Alamofire 4.0 和 Swift 3.0 的更新：
Alamofire.request(url, method: .post, parameters: parameters, encoding: JSONEncoding.default)
.responseJSON { response in
print(response)
//to get status code
if let status = response.response?.statusCode {
switch(status){
case 201:
print("example success")
default:
print("error with response status: \(status)")
}
}
//to get JSON return value
if let result = response.result.value {
let JSON = result as! NSDictionary
print(JSON)
}
}
回答by Vikram Pote
like above mention you can use SwiftyJSON library and get your values like i have done below
如上所述，您可以使用 SwiftyJSON 库并获取您的值，就像我在下面所做的那样
Alamofire.request(.POST, "MY URL", parameters:parameters, encoding: .JSON) .responseJSON
{
(request, response, data, error) in
var json = JSON(data: data!)
println(json)
println(json["productList"][1])
}
my json product list return from script
我的 json 产品列表从脚本返回
{ "productList" :[
{"productName" : "PIZZA","id" : "1","productRate" : "120.00","productDescription" : "PIZZA AT 120Rs","productImage" : "uploads\/pizza.jpeg"},
{"productName" : "BURGER","id" : "2","productRate" : "100.00","productDescription" : "BURGER AT Rs 100","productImage" : "uploads/Burgers.jpg"}
]
}
output :
输出 ：
{
"productName" : "BURGER",
"id" : "2",
"productRate" : "100.00",
"productDescription" : "BURGER AT Rs 100",
"productImage" : "uploads/Burgers.jpg"
}
回答by mick80234
I found the answer on GitHub for Swift2
我在 GitHub 上找到了Swift2的答案
https://github.com/Alamofire/Alamofire/issues/641
https://github.com/Alamofire/Alamofire/issues/641
Alamofire.request(.GET, URLString, parameters: ["foo": "bar"])
.responseJSON { request, response, result in
switch result {
case .Success(let JSON):
print("Success with JSON: \(JSON)")
case .Failure(let data, let error):
print("Request failed with error: \(error)")
if let data = data {
print("Response data: \(NSString(data: data, encoding: NSUTF8StringEncoding)!)")
}
}
}
回答by iljn
Swift 3, Alamofire 4.4, and SwiftyJSON:
Swift 3、Alamofire 4.4 和 SwiftyJSON：
Alamofire.request(url, method: .get)
.responseJSON { response in
if response.data != nil {
let json = JSON(data: response.data!)
let name = json["people"][0]["name"].string
if name != nil {
print(name!)
}
}
}
That will parse this JSON input:
这将解析此 JSON 输入：
{
people: [
{ name: 'John' },
{ name: 'Dave' }
]
}
回答by KenL
I'm neither a JSON expert nor a Swift expert, but the following is working for me. :) I have extracted the code from my current app, and only changed "MyLog to println", and indented with spaces to get it to show as a code block (hopefully I didn't break it).
我既不是 JSON 专家也不是 Swift 专家，但以下内容对我有用。:) 我已经从我当前的应用程序中提取了代码，只将“MyLog 改为 println”，并用空格缩进以使其显示为代码块（希望我没有破坏它）。
func getServerCourseVersion(){
Alamofire.request(.GET,"\(PUBLIC_URL)/vtcver.php")
.responseJSON { (_,_, JSON, _) in
if let jsonResult = JSON as? Array<Dictionary<String,String>> {
let courseName = jsonResult[0]["courseName"]
let courseVersion = jsonResult[0]["courseVersion"]
let courseZipFile = jsonResult[0]["courseZipFile"]
println("JSON: courseName: \(courseName)")
println("JSON: courseVersion: \(courseVersion)")
println("JSON: courseZipFile: \(courseZipFile)")
}
}
}
Hope this helps.
希望这可以帮助。
Edit:
编辑：
For reference, here is what my PHP Script returns:
作为参考，这是我的 PHP 脚本返回的内容：
[{"courseName": "Training Title","courseVersion": "1.01","courseZipFile": "101/files.zip"}]
回答by Giang
swift 3
迅捷 3
pod 'Alamofire', '~> 4.4'
pod 'SwiftyJSON'
File json format:
{
"codeAd": {
"dateExpire": "2017/12/11",
"codeRemoveAd":"1231243134"
}
}
import Alamofire
import SwiftyJSON
private func downloadJson() {
Alamofire.request("https://yourlinkdownloadjson/abc").responseJSON { response in
debugPrint(response)
if let json = response.data {
let data = JSON(data: json)
print("data\(data["codeAd"]["dateExpire"])")
print("data\(data["codeAd"]["codeRemoveAd"])")
}
}
}
回答by Carl Smith
I found a way to convert the response.result.value (inside an Alamofire responseJSON closure) into JSON format that I use in my app.
我找到了一种将 response.result.value（在 Alamofire responseJSON 闭包内）转换为我在我的应用程序中使用的 JSON 格式的方法。
I'm using Alamofire 3 and Swift 2.2.
我正在使用 Alamofire 3 和 Swift 2.2。
Here's the code I used:
这是我使用的代码：
Alamofire.request(.POST, requestString,
parameters: parameters,
encoding: .JSON,
headers: headers).validate(statusCode: 200..<303)
.validate(contentType: ["application/json"])
.responseJSON { (response) in
NSLog("response = \(response)")
switch response.result {
case .Success:
guard let resultValue = response.result.value else {
NSLog("Result value in response is nil")
completionHandler(response: nil)
return
}
let responseJSON = JSON(resultValue)
// I do any processing this function needs to do with the JSON here
// Here I call a completionHandler I wrote for the success case
break
case .Failure(let error):
NSLog("Error result: \(error)")
// Here I call a completionHandler I wrote for the failure case
return
}
回答by Luthfi Rahman
I usually use Glosslibrary to serialize or deserialize JSON in iOS. For example, I have JSON that looks like this:
我通常使用Gloss库在 iOS 中序列化或反序列化 JSON。例如，我有如下所示的 JSON：
{"ABDC":[{"AB":"qwerty","CD":"uiop"}],[{"AB":"12334","CD":"asdf"}]}
First, I model the JSON array in Gloss struct:
首先，我在 Gloss 结构中对 JSON 数组进行建模：
Struct Struct_Name: Decodable {
let IJ: String?
let KL: String?
init?(json: JSON){
self.IJ = "AB" <~~ json
self.KL = "CD" <~~ json
}
}
And then in Alamofire responseJSON, I do this following thing:
然后在 Alamofire responseJSON 中，我执行以下操作：
Alamofire.request(url, method: .get, paramters: parametersURL).validate(contentType: ["application/json"]).responseJSON{ response in
switch response.result{
case .success (let data):
guard let value = data as? JSON,
let eventsArrayJSON = value["ABDC"] as? [JSON]
else { fatalError() }
let struct_name = [Struct_Name].from(jsonArray: eventsArrayJSON)//the JSON deserialization is done here, after this line you can do anything with your JSON
for i in 0 ..< Int((struct_name?.count)!) {
print((struct_name?[i].IJ!)!)
print((struct_name?[i].KL!)!)
}
break
case .failure(let error):
print("Error: \(error)")
break
}
}
The output from the code above:
上面代码的输出：
qwerty
uiop
1234
asdf
回答by Sazzad Hissain Khan
Swift 5
斯威夫特 5
class User: Decodable {
var name: String
var email: String
var token: String
enum CodingKeys: String, CodingKey {
case name
case email
case token
}
public required init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
self.name = try container.decode(String.self, forKey: .name)
self.email = try container.decode(String.self, forKey: .email)
self.token = try container.decode(String.self, forKey: .token)
}
}
Alamofire API
阿拉莫菲尔 API
Alamofire.request("url.endpoint/path", method: .get, parameters: params, encoding: URLEncoding.queryString, headers: nil)
.validate()
.responseJSON { response in
switch (response.result) {
case .success( _):
do {
let users = try JSONDecoder().decode([User].self, from: response.data!)
print(users)
} catch let error as NSError {
print("Failed to load: \(error.localizedDescription)")
}
case .failure(let error):
print("Request error: \(error.localizedDescription)")
}
回答by iGhost
This was build with Xcode 10.1 and Swift 4
这是使用 Xcode 10.1 和 Swift 4 构建的
Perfect combination "Alamofire"(4.8.1) and "SwiftyJSON"(4.2.0). First you should install both pods
“Alamofire”（4.8.1）和“SwiftyJSON”（4.2.0）的完美结合。首先，您应该安装两个 Pod
pod 'Alamofire'andpod 'SwiftyJSON'
pod 'Alamofire'和pod 'SwiftyJSON'
The server response in JSON format:
JSON 格式的服务器响应：
{
"args": {},
"headers": {
"Accept": "*/*",
"Accept-Encoding": "gzip;q=1.0, compress;q=0.5",
"Accept-Language": "en;q=1.0",
"Host": "httpbin.org",
"User-Agent": "AlamoFire TEST/1.0 (com.ighost.AlamoFire-TEST; build:1; iOS 12.1.0) Alamofire/4.8.1"
},
"origin": "200.55.140.181, 200.55.140.181",
"url": "https://httpbin.org/get"
}
In this case I want print the "Host" info : "Host": "httpbin.org"
在这种情况下，我想打印“主机”信息：“主机”：“httpbin.org”
Alamofire.request("https://httpbin.org/get").validate().responseJSON { response in
switch response.result {
case .success:
print("Validation Successful)")
if let json = response.data {
do{
let data = try JSON(data: json)
let str = data["headers"]["Host"]
print("DATA PARSED: \(str)")
}
catch{
print("JSON Error")
}
}
case .failure(let error):
print(error)
}
}
Keep Calm and happy Code
保持冷静和快乐代码
