C++ 如何初始化构造函数需要两个或多个参数的对象数组？
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How can I initialize an array of objects whose constructor require two or more arguments?
提问by Yishu Fang
suggest we have an array of class A's objects, and class A's constructor require two arguments, like this:
建议我们有一个 A 类对象的数组，A 类的构造函数需要两个参数，如下所示：
class A
{
public:
A( int i, int j ) {}
};
int main()
{
const A a[3] = { /*How to initialize*/ };
return 0;
}
How to initialize that array?
如何初始化该数组？
回答by Kerrek SB
Say:
说：
const A a[3] = { {0,0}, {1,1}, {2,2} };
On older compilers, and assuming Ahas an accessible copy constructor, you have to say:
在较旧的编译器上，并假设A有一个可访问的复制构造函数，您必须说：
const A a[3] = { A(0,0), A(1,1), A(2,2) };
C++ used to be pretty deficient with respect to arrays (certain initializations just were not possible at all), and this got a little better in C++11.
C++ 过去在数组方面非常有缺陷（某些初始化根本不可能），而这在 C++11 中变得更好一些。
回答by Dietmar Kühl
As long as the type has a copy constructior (whether synthesized or explicitly defined) the following works:
只要类型具有复制构造函数（无论是合成的还是显式定义的），以下工作：
A array[] = { A(1, 3), A(3, 4), A(5, 6) };
This work both with C++2003 and C++ 2011. The solution posted by KerrekSB certainly does not work with C++ 2003 but may work withC++ 2011 (I'm not sure if it works there).
这适用于 C++2003 和 C++ 2011。KerrekSB 发布的解决方案当然不适用于 C++ 2003，但可能适用于 C++ 2011（我不确定它是否适用于那里）。
回答by James Shao
you can provide a default constructor and initialize your array as normal. After successful initialization, use a loop to reassign values to each member
您可以提供一个默认构造函数并像往常一样初始化您的数组。初始化成功后，使用循环为每个成员重新赋值
回答by hamed
i think it should be like this
我觉得应该是这样
const A a[3] = { A(1, 2), A(3, 4), A(5, 6) };
const A a[3] = { A(1, 2), A(3, 4), A(5, 6) };
