C# 如何保留 Regex.Split 的分隔符？
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How to keep the delimiters of Regex.Split?
提问by
I'd like to split a string using the Splitfunction in the Regexclass. The problem is that it removesthe delimiters and I'd like to keep them. Preferably as separate elements in the splitee.
我想使用类中的Split函数拆分字符串Regex。问题是它删除了分隔符，我想保留它们。最好作为被拆分对象中的单独元素。
According to other discussionsthat I've found, there are only inconvenient ways to achieve that.
根据我发现的其他讨论，只有不方便的方法才能实现这一目标。
Any suggestions?
有什么建议？
采纳答案by Markus Jarderot
Just put the pattern into a capture-group, and the matches will also be included in the result.
只需将模式放入捕获组中，匹配项也将包含在结果中。
string[] result = Regex.Split("123.456.789", @"(\.)");
Result:
结果：
{ "123", ".", "456", ".", "789" }
This also works for many other languages:
这也适用于许多其他语言：
- JavaScript:
"123.456.789".split(/(\.)/g) - Python:
re.split(r"(\.)", "123.456.789") - Perl:
split(/(\.)/g, "123.456.789")
- JavaScript:
"123.456.789".split(/(\.)/g) - 蟒蛇：
re.split(r"(\.)", "123.456.789") - 珀尔：
split(/(\.)/g, "123.456.789")
(Not Java though)
（虽然不是Java）
回答by Michael Ross
Add them back:
将它们添加回来：
string[] Parts = "A,B,C,D,E".Split(',');
string[] Parts2 = new string[Parts.Length * 2 - 1];
for (int i = 0; i < Parts.Length; i++)
{
Parts2[i * 2] = Parts[i];
if (i < Parts.Length - 1)
Parts2[i * 2 + 1] = ",";
}
回答by Guffa
Use Matchesto find the separators in the string, then get the values and the separators.
使用Matches查找字符串中的分隔符，然后得到的值和分隔符。
Example:
例子：
string input = "asdf,asdf;asdf.asdf,asdf,asdf";
var values = new List<string>();
int pos = 0;
foreach (Match m in Regex.Matches(input, "[,.;]")) {
values.Add(input.Substring(pos, m.Index - pos));
values.Add(m.Value);
pos = m.Index + m.Length;
}
values.Add(input.Substring(pos));
回答by I4V
Say that input is "abc1defg2hi3jkl" and regex is to pick out digits.
假设输入是“abc1defg2hi3jkl”，正则表达式是挑选数字。
String input = "abc1defg2hi3jkl";
var parts = Regex.Matches(input, @"\d+|\D+")
.Cast<Match>()
.Select(m => m.Value)
.ToList();
Parts would be: abc1defg2hi3jkl
部分将是： abc1defg2hi3jkl
