ios 关闭所有打开的视图控制器的单个函数
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/33520899/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
single function to dismiss all open view controllers
提问by user2363025
I have an app which is a single view application. I have a navigation controller linked up to all child controllers from the root view controller.
我有一个应用程序，它是一个单视图应用程序。我有一个导航控制器从根视图控制器链接到所有子控制器。
In each child controller, I have a logout button. I'm wondering if I can have a single function I can call which will dismiss all the controllers which have been open along along the way, no matter which controller was currently open when the user presses logout?
在每个子控制器中，我都有一个注销按钮。我想知道我是否可以调用一个函数来关闭所有沿途打开的控制器，无论用户按下注销时当前打开的是哪个控制器？
My basic start:
我的基本开始：
func tryLogout(){
self.dismissViewControllerAnimated(true, completion: nil)
let navigationController = UINavigationController(rootViewController: UIStoryboard(name: "Main", bundle: nil).instantiateViewControllerWithIdentifier("LoginViewController") )
self.presentViewController(navigationController, animated: true, completion: nil)
}
I am looking for the most memory efficient way of carrying out this task. I will put my logout function in a separate utils file, but then I can't use self. And I still have the issue of knowing which controllers to dismiss dynamically.
我正在寻找执行此任务的最有效的内存方式。我会将我的注销功能放在一个单独的 utils 文件中，但是我不能使用 self. 而且我仍然有知道要动态解雇哪些控制器的问题。
UpdatePop to root view controller has been suggested. So my attempt is something like:
已建议将 Pop更新为根视图控制器。所以我的尝试是这样的：
func tryLogout(ViewController : UIViewController){
print("do something")
dispatch_async(dispatch_get_main_queue(), {
ViewController.navigationController?.popToRootViewControllerAnimated(true)
return
})
}
Would this be the best way to achieve what I'm after?
这会是实现我所追求的最佳方式吗？
回答by Liam
You can call :
您可以致电：
self.view.window!.rootViewController?.dismiss(animated: false, completion: nil)
Should dismiss all view controllers above the root view controller.
应该关闭根视图控制器上方的所有视图控制器。
回答by Bijender Singh Shekhawat
Updated answer for Swift 4and swift 5
Swift 4和Swift 5 的更新答案
UIApplication.shared.keyWindow?.rootViewController?.dismiss(animated: true, completion: nil)
and when you use navigationController
当你使用 navigationController
self.navigationController?.popToRootViewController(animated: true)
回答by Naishta
Swift 4:
斯威夫特 4：
To dismiss any unwanted residue Modal ViewControllers, I used this and worked well without retaining any navigation stack references.
为了消除任何不需要的残留物 Modal ViewControllers，我使用了它并且在不保留任何导航堆栈引用的情况下运行良好。
UIApplication.shared.keyWindow?.rootViewController?.dismiss(animated: false, completion: nil)
self.view.window!did crash for my case possibly because its a Modal screen and had lost the reference to the window.
self.view.window!我的情况确实崩溃了，可能是因为它是一个模态屏幕并且丢失了对窗口的引用。
回答by markhorrocks
Swift3
斯威夫特3
navigationController?.popToRootViewControllerAnimated(true)
回答by Nitin Alabur
Take a look at how unwind segues work. Its super simple, and lets you dismiss/pop to a certain viewcontroller in the heirarchy, even if it consists of a complex navigation (nested pushed and or presented view controllers), without much code.
看看 unwind segue 是如何工作的。它非常简单，即使它由复杂的导航（嵌套的推送和/或呈现的视图控制器）组成，也可以让您关闭/弹出到层次结构中的某个视图控制器，无需太多代码。
Here's a very good answer (by smilebot) that shows how to use unwind segues to solve your problem https://stackoverflow.com/a/27463286/503527
这是一个非常好的答案（来自smilebot），它展示了如何使用展开segues来解决您的问题 https://stackoverflow.com/a/27463286/503527
回答by Pardeep Kumar
works for Swift 3.0 +
适用于 Swift 3.0 +
self.view.window!.rootViewController?.dismiss(animated: true, completion: nil)
回答by Yun CHEN
If you have a customed UITabbarController, then try dismiss top viewController in UITabbarController by:
如果您有自定义的 UITabbarController，请尝试通过以下方式关闭 UITabbarController 中的 top viewController：
class MainTabBarController: UITabBarController {
func aFuncLikeLogout() {
self.presentedViewController?.dismiss(animated: false, completion: nil)
//......
}
}
回答by Rahul Panzade
SwiftUsed this to jump directly on your ROOT Navigation controller.
Swift使用它直接跳转到您的 ROOT 导航控制器。
self.navigationController?.popToRootViewController(animated: true)
self.navigationController?.popToRootViewController(animated: true)
