bash 如何枚举文件列表
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How to enumerate a list of files
提问by Devavrata
I want to get a numbered list of files, e.g. if I have these files:
我想获得一个编号的文件列表，例如，如果我有这些文件：
a.pdf
b.pdf
c
then it should be listed as:
那么它应该被列为：
1 a.pdf
2 b.pdf
3 c
回答by Devavrata
You can do it two ways:-
1st one :-ls -1 | awk '{print NR,$0}'
您可以通过两种方式做到这一点：-
第一种：-ls -1 | awk '{print NR,$0}'
2nd one:-ls -1 | cat -n
You must prefer 2nd one but choose whatever you like. :-)
第二个：-ls -1 | cat -n
您必须更喜欢第二个，但可以选择任何您喜欢的。:-)
回答by Devavrata
If you want to avoid parsing the output of ls(which you do), you can do something like this:
如果您想避免解析ls（您所做的）的输出，您可以执行以下操作：
$ counter=1; for f in *; do printf "%2d %s\n" $((counter++)) "$f"; done
1 a.pdf
2 b.pdf
3 c
I only mention this because it's the path for doing more sophisticated things, not just enumerating.
我之所以提到这一点，是因为它是做更复杂的事情的途径，而不仅仅是枚举。
回答by BMW
If your system has command nl, it will be easier. ( I can confirm nlcommand is exist in cygwin, aix and solaris system, then it should be popular command in most unix system)
如果您的系统有 command nl，它会更容易。（我可以确认nl命令存在于cygwin、aix和solaris系统中，那么它应该是大多数unix系统中流行的命令）
ls |nl
回答by Scott Lawrence
You can do this without awk, trivially. ls -1 | cat -n.
你可以不用 awk 就可以做到这一点，很简单。ls -1 | cat -n.
Or, with awk:
或者，使用 awk：
ls -1 | awk '{printf "%d %s\n", NR, ls | awk '{print NR, ##代码##}'
;}'
回答by Floris
Not sure why you need to use awkbut here you go:
不知道为什么你需要使用，awk但你去吧：
updated$0is better than $1since it will print the entire file name even with spaces (as hinted at by BroSlow)
更新$0比$1因为即使有空格也会打印整个文件名（如 BroSlow 所暗示的那样）更好
Note - you do notneed to use the -1flag with lswhen the output is another process - it becomes the default option. Only when you want to force output to the terminal with one file per line do you need to use it.
注-你不是需要使用-1国旗ls时，输出也是一个过程-它成为默认选项。只有当你想强制输出到每行一个文件的终端时，你才需要使用它。
