Java 删除列表的最后一个元素
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Remove last element of a list
提问by Kenneth Yong
I've been tasked to do the below in a newbie Java tutorial on ArrayList
我的任务是在 ArrayList 的新手 Java 教程中执行以下操作
// 1) Declare am ArrayList of strings
// 2) Call the add method and add 10 random strings
// 3) Iterate through all the elements in the ArrayList
// 4) Remove the first and last element of the ArrayList
// 5) Iterate through all the elements in the ArrayList, again.
Below is my code
下面是我的代码
import java.util.ArrayList;
import java.util.Random;
public class Ex1_BasicArrayList {
public static void main(String[] args) {
ArrayList<String> list = new ArrayList<String>();
for (int i = 0; i <= 10; i++){
Random rand = new Random();
String randy = String.valueOf(rand);
list.add(randy );
}
for (int i = 0; i < list.size(); i++){
System.out.print(list.get(i));
}
list.remove(0);
list.remove(list.size());
for (int i = 0; i < list.size(); i++){
System.out.print(list.get(i));
}
}
}
The code runs, but I get the below error message when it runs. Any ideas on what I'm doing wrong?
代码运行，但我在运行时收到以下错误消息。关于我做错了什么的任何想法？
[email protected]@[email protected]@[email protected]@[email protected]@[email protected]@6bc7c054Exception in thread "main" java.lang.IndexOutOfBoundsException: Index: 10, Size: 10
at java.util.ArrayList.rangeCheck(Unknown Source)
at java.util.ArrayList.remove(Unknown Source)
at apollo.exercises.ch08_collections.Ex1_BasicArrayList.main(Ex1_BasicArrayList.java:23)
采纳答案by Reimeus
Listindices go from 0to list.size() - 1. Exceeding the upper bound results in the IndexOutOfBoundsException
List索引从0到list.size() - 1。超过上限会导致IndexOutOfBoundsException
list.remove(list.size() - 1);
回答by Zoltán
Your list has 11 elements, their indices are 0-10. When you call list.remove(list.size());, you are telling it to remove the element at index 11 (because the size of the list is 11), but that index is out of bounds.
您的列表有 11 个元素，它们的索引为 0-10。当您调用 时list.remove(list.size());，您是在告诉它删除索引 11 处的元素（因为列表的大小为 11），但该索引超出范围。
The index of the last element of any list is always list.size() - 1.
任何列表的最后一个元素的索引总是list.size() - 1。
