C语言 如何在C编程语言中比较两个数组？
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How to compare two arrays in C programming language?
提问by Hassen Fatima
I want to compare two different arrays which are both int. One array is static and contains numbers from 1 to 10 and second arrays asks user to enter ten different numbers and the program checks which elements from both arrays are equal.
我想比较两个不同的数组，它们都是int. 第一个数组是静态的，包含 1 到 10 的数字，第二个数组要求用户输入十个不同的数字，程序会检查两个数组中的哪些元素相等。
#include <stdio.h>
int main(void) {
int array1[] = {1,2,3,4,5,6,7,8,9,10};
int array2[10];
int i;
for (i=0;i<11;i++) {
printf("Enter numbers: ");
scanf("%d", &array2);
}
for (i=0;i<11;i++) {
if (array1[i] != array2[i]) {
printf("Not equal \n");
}
else {
printf("They are equal. \n");
}
}
}
The program always say not equal even if I enter a number that is equal to a number stored in first array.
即使我输入的数字等于存储在第一个数组中的数字，程序也总是说不相等。
采纳答案by Inisheer
scanf("%d", &array2);
You are never updating the index of array2when getting a value from input.
array2从输入中获取值时，您永远不会更新索引。
Try
尝试
scanf("%d", &array2[i]);
As for comparing, you can also use memcmpto compare memory:
至于比较，也可以使用memcmp比较内存：
memcmp(array1, array2, sizeof(array1));
回答by mathematician1975
Arrays use zero based indices for a start. You are incorrectly populating array2so you probably want to change your first loop to the following
数组使用基于零的索引作为开始。您的填充不正确，array2因此您可能希望将第一个循环更改为以下内容
for (i=0;i<10;i++)
{
printf("Enter numbers: ");
scanf("%d", &array2[i]);
}
as your current code is simply passing the address of array2as argument to scanf.
因为您当前的代码只是将array2as 参数的地址传递给scanf.
Then change the second loop conditional to
然后将第二个循环条件改为
for (i=0;i<10;i++)
in your comparison loop so that you do not access items beyond your array boundaries.
在您的比较循环中，以便您不会访问超出数组边界的项目。
Currently your second loop is accessing items at indices 0 to 10 - but there are only 10 items present in array1so you have undefined behaviour with your current code.
目前，您的第二个循环正在访问索引 0 到 10 处的项目 - 但其中只有 10 个项目，array1因此您当前的代码存在未定义的行为。
回答by Enamul Hassan
#include <stdio.h>
int main(void) {
int array1[] = {1,2,3,4,5,6,7,8,9,10};
int array2[10];
int i;
for (i=0;i<10;i++) { //fixed the range here
printf("Enter numbers: ");
scanf("%d", &array2[i]); //fixed the indexing
}
for (i=0;i<10;i++) { //fixed the range here
if (array1[i] != array2[i]) {
printf("Not equal \n");
}
else {
printf("They are equal. \n");
}
}
}
回答by raju_singha
I am a beginner and I have this idea about comparing two arrays.Hope It might help someone like me.
我是初学者，我有比较两个数组的想法。希望它可以帮助像我这样的人。
/***compare two array: all elements are same or not(if not sorted
)***/
#include<stdio.h>
int main()
{
int n;
scanf("%d", &n);
int array1[n], array2[n];
int i, j;
for(i=0; i<n; i++)
{
scanf("%d", &array1[i]);
}
for(i=0; i<n; i++)
{
scanf("%d", &array2[i]);
}
int flg=0;
for(i = 0; i < n; i++)
{
for(j=0; j<n; j++)
{
if(array1[i] == array2[j])
{
flg += 1;
break;
}
}
}
if(flg == n)
{
printf("All The Elements of array1 is present in array2... :)");
}
else
{
printf("All THe Elements of array1 is not present in array2 :(");
}
return 0;
}
}
回答by Goma Joaquim
I am trying to respond to the answer, even though I am a beginner to C program.
尽管我是 C 程序的初学者，但我正在尝试回应答案。
According to your program written above, you are inputting and holding values to int array2[10]which has 11 elements.
根据您上面编写的程序，您正在输入和保存int array2[10]具有 11 个元素的值。
Remember that the first element of this array is indexed by zero. Ex: array2[0], until it reaches the last element which is array2[10], you have counted 11.
请记住，该数组的第一个元素的索引为零。例如：array2[0]，直到它到达最后一个元素，即array2[10]，您已经数了 11。
Now array1has the pre-defined values write which will be compared to your input values. Enter and store your values into array2[].
现在array1有预定义的值写入，将与您的输入值进行比较。输入您的值并将其存储到array2[].
#include <stdio.h>
int main(void) {
int array1[] = {1,2,3,4,5,6,7,8,9,10};
int array2[10];
int i;
for (i=0;i<10;i++) { //fixed the range here
printf("Enter numbers: ");
scanf("%d", &array2[i]); //fixed the indexing
if (array1[i] != array2[i]) {
printf("Not equal \n");
}
else {
printf("They are equal. \n");
}
}
}
