在 TypeScript 中将数组作为参数传递
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Passing array as arguments in TypeScript
提问by langtu
I have two methods:
我有两种方法：
static m1(...args: any[]) {
//using args as array ...
}
static m2(str: string, ...args: any[]){
//do something
//....
//call to m1
m1(args);
}
The call to m1(1,2,3)works as expect. However, the call m2("abc",1,2,3)will pass to m1([1,2,3]), not as expect: m1(1,2,3).
调用m1(1,2,3)按预期工作。但是，调用m2("abc",1,2,3)将传递到m1([1,2,3])，而不是预期：m1(1,2,3)。
So, how to pass argsas arguments when make call to m1in m2?
那么，如何args在调用m1in时作为参数传递m2？
采纳答案by user703016
T.m1.apply(this, args);
Where T is the enclosing class of m1.
其中 T 是 的封闭类m1。
回答by Rick Love
Actually, using the ...again when calling the method will work.
实际上，...在调用该方法时再次使用该方法是可行的。
It generates the apply call for you in javascript.
它在 javascript 中为您生成应用调用。
static m1(...args: any[]) {
//using args as array ...
}
static m2(str: string, ...args: any[]){
//do something
//....
//call to m1
// m1(args);
// BECOMES
m1(...args);
}
