php 使用php获取两个日期之间的总时差
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Get total time difference between two dates using php
提问by meginjoy
Possible Duplicate:
How to calculate the difference between two dates using PHP?
可能的重复：
如何使用 PHP 计算两个日期之间的差异？
Here i mention two times with its date
在这里我提到了两次它的日期
2008-12-13 10:42:00
2010-10-20 08:10:00
2008-12-13 10:42:00
2010-10-20 08:10:00
I want to get total time difference in (h:m:s) format
我想以 (h:m:s) 格式获得总时差
回答by futureal
If you are using or able to use PHP 5.3.x or later, you can use its DateTime object functionality:
如果您正在使用或能够使用 PHP 5.3.x 或更高版本，则可以使用其 DateTime 对象功能：
$date_a = new DateTime('2010-10-20 08:10:00');
$date_b = new DateTime('2008-12-13 10:42:00');
$interval = date_diff($date_a,$date_b);
echo $interval->format('%h:%i:%s');
You can play with the format in a variety of ways, and once you have dates in DateTime objects, you can take advantage of a lot of different functionality, for example comparison via normal operators. See the manual for more: http://us3.php.net/manual/en/datetime.diff.php
您可以通过多种方式使用该格式，一旦您在 DateTime 对象中拥有日期，您就可以利用许多不同的功能，例如通过普通运算符进行比较。有关更多信息，请参阅手册：http: //us3.php.net/manual/en/datetime.diff.php
回答by futureal
what im using:
我在用什么：
$seconds = strtotime("2010-10-20 08:10:00") - strtotime("2008-12-13 10:42:00");
$days = floor($seconds / 86400);
$hours = floor(($seconds - ($days * 86400)) / 3600);
$minutes = floor(($seconds - ($days * 86400) - ($hours * 3600))/60);
$seconds = floor(($seconds - ($days * 86400) - ($hours * 3600) - ($minutes*60)));
you can format now in your way
你现在可以按照你的方式格式化
回答by Ibu
You can use the the strtotime functionto turn the time to integers and subtract them.
您可以使用strtotime 函数将时间转换为整数并减去它们。
$time1 = strtotime("2008-12-13 10:42:00");
$time2 = strtotime("2010-10-20 08:10:00");
$diff = $time2-$time1;
// the difference in int. then you can divide by 60,60,24 and
// so on to get the h:m:s out of it
