Java 从 int 值创建 BigInteger 实例的最有效方法是什么？
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What is the most effective way to create BigInteger instance from int value?
提问by Roman
I have a method (in 3rd-party library) with BigInteger parameter:
我有一个带有 BigInteger 参数的方法（在第 3 方库中）：
public void setValue (BigInteger value) { ... }
I don't need 'all its power', I only need to work with integers. So, how can I pass integers to this method? My solution is to get string value from int value and then create BigInteger from string:
我不需要'所有的力量'，我只需要处理整数。那么，如何将整数传递给这个方法呢？我的解决方案是从 int 值获取字符串值，然后从字符串创建 BigInteger：
int i = 123;
setValue (new BigInteger ("" + i));
Are there any other (recommended) ways to do that?
有没有其他（推荐的）方法可以做到这一点？
采纳答案by Michael Borgwardt
BigInteger.valueOf(i);
回答by Bozhidar Batsov
Use the static method BigInteger.valueOf(long number). intvalues will be promoted to longautomatically.
使用静态方法BigInteger.valueOf(long number)。int值将被long自动提升。
回答by Petar Minchev
You can use this static method: BigInteger.valueOf(long val)
您可以使用此静态方法： BigInteger.valueOf(long val)
回答by Paul Croarkin
setValue(BigInteger.valueOf(123L));
