从纬度和经度获取 PHP 时区名称？
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Get PHP Timezone Name from Latitude and Longitude?
提问by Navarr
Is there a way get the timezone of a user by their latitude and longitude? And not just the offset, but the actual timezone they're in.
有没有办法通过纬度和经度获取用户的时区？不仅是偏移量，还有它们所在的实际时区。
Essentially, I'm searching for the polar opposite of DateTimeZone::getLocation which returns the latitude and longitude for a certain timezone.
从本质上讲，我正在寻找 DateTimeZone::getLocation 的极端对立面，它返回某个时区的纬度和经度。
采纳答案by thomasfedb
Geonames should do the job nicely:
Geonames 应该很好地完成这项工作：
They've also got a php library.
他们还有一个 php 库。
回答by j-bin
For those who wants to get timezone from country code, latitude and longitude. ( easy to get it if you have a geoip module installed on your server )
对于那些想要从国家代码、纬度和经度获取时区的人。（如果您的服务器上安装了 geoip 模块，则很容易获得它）
Try this, I've added a distance calculation - only for those countries which has multiple timezones. Ah, and the country code is a two letter ISO code.
试试这个，我添加了一个距离计算 - 仅适用于具有多个时区的国家。啊，国家代码是两个字母的 ISO 代码。
// ben@jp
function get_nearest_timezone($cur_lat, $cur_long, $country_code = '') {
$timezone_ids = ($country_code) ? DateTimeZone::listIdentifiers(DateTimeZone::PER_COUNTRY, $country_code)
: DateTimeZone::listIdentifiers();
if($timezone_ids && is_array($timezone_ids) && isset($timezone_ids[0])) {
$time_zone = '';
$tz_distance = 0;
//only one identifier?
if (count($timezone_ids) == 1) {
$time_zone = $timezone_ids[0];
} else {
foreach($timezone_ids as $timezone_id) {
$timezone = new DateTimeZone($timezone_id);
$location = $timezone->getLocation();
$tz_lat = $location['latitude'];
$tz_long = $location['longitude'];
$theta = $cur_long - $tz_long;
$distance = (sin(deg2rad($cur_lat)) * sin(deg2rad($tz_lat)))
+ (cos(deg2rad($cur_lat)) * cos(deg2rad($tz_lat)) * cos(deg2rad($theta)));
$distance = acos($distance);
$distance = abs(rad2deg($distance));
// echo '<br />'.$timezone_id.' '.$distance;
if (!$time_zone || $tz_distance > $distance) {
$time_zone = $timezone_id;
$tz_distance = $distance;
}
}
}
return $time_zone;
}
return 'unknown';
}
//timezone for one NY co-ordinate
echo get_nearest_timezone(40.772222,-74.164581) ;
// more faster and accurate if you can pass the country code
echo get_nearest_timezone(40.772222, -74.164581, 'US') ;
回答by dav
A good resource is the Google Time Zone API.
一个很好的资源是 Google Time Zone API。
Documentation: https://developers.google.com/maps/documentation/timezone/
文档：https: //developers.google.com/maps/documentation/timezone/
It takes latitudeand longitudeand returns array like this:
它接受latitude并longitude返回这样的数组：
array(
'dstOffset' => (int) 3600,
'rawOffset' => (int) -18000,
'status' => 'OK',
'timeZoneId' => 'America/New_York',
'timeZoneName' => 'Eastern Daylight Time'
)
...but there are some limits:
...但有一些限制：
[updated 2019]The Google Time Zone API has usage limits in place. Basically, billing must be enabled on your project, but a $200 USD "Google Maps Platform credit" is applied each month (so in most cases your first 40,000 Time Zone API calls/month would be free of charge).
[2019 年更新]Google 时区 API 有使用限制。基本上，必须对您的项目启用计费，但每月应用 200 美元的“Google Maps Platform 信用”（因此在大多数情况下，您每月前 40,000 次时区 API 调用是免费的）。
回答by Uddhav Kambli
I did a timezone solution recently in an 8 hour long hackathon. It's quickly put together and I'd love to develop it further and sell it as a product but since there is no way for me to do it, I've open sourced it at my github.
我最近在 8 小时的黑客马拉松中做了一个时区解决方案。它很快就组装好了，我很想进一步开发它并将其作为产品出售，但由于我没有办法做到这一点，我已经在我的 github 上开源了它。
There is a demotoo but it may go down if it hits resource limits. It's a free webapp on Google App Engine.
也有一个演示，但如果达到资源限制，它可能会关闭。它是 Google App Engine 上的免费网络应用程序。
You can definitely optimize/augment this further in wrt - running time, space, data - to suit your needs.
您绝对可以在 wrt 中进一步优化/增强它 - 运行时间、空间、数据 - 以满足您的需求。
回答by Jiho Kang
The Yahoo places API provides timezone information via reverse geolocation.
雅虎地点 API 通过反向地理定位提供时区信息。
Check it out.
一探究竟。
http://developer.yahoo.com/geo/placefinder/guide/requests.html
http://developer.yahoo.com/geo/placefinder/guide/requests.html
回答by Dziamid
How about finding the closest point to the one in the list of all timezone locations? I wonder how accurate is this?
如何在所有时区位置列表中找到最接近的点？我想知道这有多准确？
UPDATE: Eventually, I came up with this snippet that works for me. This will work fine for all locations, but may not be accurate for those close to borders.
更新：最终，我想出了这个对我有用的片段。这适用于所有位置，但对于靠近边界的位置可能不准确。
/**
* Attempts to find the closest timezone by coordinates
*
* @static
* @param $lat
* @param $lng
*/
public static function getClosestTimezone($lat, $lng)
{
$diffs = array();
foreach(DateTimeZone::listIdentifiers() as $timezoneID) {
$timezone = new DateTimeZone($timezoneID);
$location = $timezone->getLocation();
$tLat = $location['latitude'];
$tLng = $location['longitude'];
$diffLat = abs($lat - $tLat);
$diffLng = abs($lng - $tLng);
$diff = $diffLat + $diffLng;
$diffs[$timezoneID] = $diff;
}
//asort($diffs);
$timezone = array_keys($diffs, min($diffs));
return $timezone[0];
}
