php 多维数组上的数组合并
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Array merge on multidimensional array
提问by Patrick Manser
Either I'm blind or I can't find this problem anywhere here on SO. Yesterday I had a problem with merging arrays, which I could fix with the help of SO. Today I have, again, a problem with merging arrays, but this time it's with multidimensional Arrays.
要么我瞎了，要么我在 SO 上的任何地方都找不到这个问题。昨天我在合并数组时遇到了问题，我可以在 SO 的帮助下解决这个问题。今天我再次遇到合并数组的问题，但这次是多维数组。
I have an array $usergroup['groups']and an array $usergroup['lang']
我有一个数组$usergroup['groups']和一个数组$usergroup['lang']
$usergroup['groups']looks like this:
$usergroup['groups']看起来像这样：
Array
(
[0] => Usergroup_Model Object
(
[id] => 1
[deleted] => 0
)
[1] => Usergroup_Model Object
(
[id] => 2
[deleted] => 0
)
[2] => Usergroup_Model Object
(
[id] => 3
[deleted] => 0
)
)
And $usergroup['lang']looks like this:
而且$usergroup['lang']是这样的：
Array
(
[0] => Usergroup_Model Object
(
[id] =>
[id_usergroup] => 1
[name] => Administratoren
[id_lang] => 1
)
[1] => Usergroup_Model Object
(
[id] =>
[id_usergroup] => 2
[name] => Benutzer
[id_lang] => 1
)
[2] => Usergroup_Model Object
(
[id] =>
[id_usergroup] => 3
[name] => G?ste
[id_lang] => 1
)
)
I want my merged array to look like this:
我希望我的合并数组如下所示：
Array
(
[0] => Usergroup_Model Object
(
[id] => 1
[id_usergroup] => 1
[name] => Administratoren
[id_lang] => 1
[deleted] => 0
)
[1] => Usergroup_Model Object
(
[id] => 2
[id_usergroup] => 2
[name] => Benutzer
[id_lang] => 1
[deleted] => 0
)
[2] => Usergroup_Model Object
(
[id] => 3
[id_usergroup] => 3
[name] => G?ste
[id_lang] => 1
[deleted] => 0
)
)
I've tried several merging functions (array_merge()and array_merge_recursive()) of PHP, the closest result I got was, that the second Array (['lang']) overwrote the first Array (['groups']). To fix that, I tried to remove the empty values on the langArray (which is always id). But that does not fix it. The code - at the moment - looks like this:
我已经尝试了PHP 的几个合并函数（array_merge()和array_merge_recursive()），我得到的最接近的结果是，第二个数组（['lang']）覆盖了第一个数组（['groups']）。为了解决这个问题，我尝试删除langArray上的空值（始终为id）。但这并不能解决问题。代码 - 目前 - 看起来像这样：
public static function getAll()
{
$usergroup['groups'] = self::find();
$usergroup['lang'] = self::findInTable(array(
'id_lang' => Language_Model::getDefaultLanguage()
), self::dbTranslationTable);
foreach ($usergroup as $ug) {
$ug = array_filter($ug, function($val) {
return $val != '';
});
}
return array_merge($ug);
}
The array_merge() on the return command doesn't seem to do anything at all, so I'm probably not gathering the data correctly or I mess something up with the Arrays (forgetting to add [], or I don't know...). I kinda miss the forest for the trees here.
return 命令中的 array_merge() 似乎根本没有做任何事情，所以我可能没有正确收集数据，或者我把数组搞砸了（忘记添加 []，或者我不知道。 ...）。我有点想念这里的树林。
Any suggestions in which direction I could go?
有什么建议可以朝哪个方向发展？
Edit:With the code provided by Pé de Le?o I was able to solve the problem. My function now looks like this:
编辑：使用 Pé de Le?o 提供的代码，我能够解决问题。我的函数现在看起来像这样：
public static function getAll()
{
$usergroup['groups'] = self::find();
$usergroup['lang'] = self::findInTable(array(
'id_lang' => Language_Model::getDefaultLanguage()
), self::dbTranslationTable);
$out = array();
foreach ($usergroup['groups'] as $key => $value) {
$out[] = (object) array_merge((array) $usergroup['lang'][$key], (array) $value);
}
return $out;
}
And the result is exactly how I wanted it!
结果正是我想要的！
回答by Expedito
$out = array();
foreach ($arr1 as $key => $value){
$out[] = (object)array_merge((array)$arr2[$key], (array)$value);
}
print_r($out)
回答by steven
maybe its not the smartest but you can try it like this, too:
也许它不是最聪明的，但你也可以这样尝试：
public static function getAll()
{
$groups = self::find();
$lang = self::findInTable(array(
'id_lang' => Language_Model::getDefaultLanguage()
), self::dbTranslationTable);
$n = array();
foreach($groups as $g) {
$id = $g['id'];
$n[$id] = $g;
}
foreach($lang as $a) {
$id = $a['id_usergroup'];
if(!isset($n[$id])){ $n[$id] = array(); }
$n[$id]['id_usergroup'] = $a['id_usergroup'];
$n[$id]['name'] = $a['name'];
$n[$id]['id_lang'] = $a['id_lang'];
}
return $n;
}
the key of the returned array will be the id of the group in this example.
在此示例中，返回数组的键将是组的 id。
回答by Owen Beresford
I have never array_merge() with objects before. I suspect you would need to have classes like UNION for it to work (i.e. public data).
我以前从未使用过 array_merge() 对象。我怀疑你需要有像 UNION 这样的类才能工作（即公共数据）。
- Assertion: this is your data structure and it won't change much.
- Assertion: if you had provided var_export() output rather than print_r() in the samples at the top, I could have executed the following (to test it)...
- It would be better to use a more specific class in the last used cast statement, but I don't know your class hierarchy ~ Usergroup_Model?
This answer ignore anything to do with getDefaultLanguage() as that wasn't part of the question.
$ITEMS=count($usergroup['groups']); $out=array(); for($i=0; $i<$ITEMS; $i++) { if(isset($usergroup['lang'][$i])) { $out[]=(object)array_merge((array)$usergroup['groups'][$i], (array)$usergroup['lang'][$i]); } else { $out[]=$usergroup['groups'][$i]; } }
- 断言：这是您的数据结构，不会有太大变化。
- 断言：如果您在顶部的示例中提供了 var_export() 输出而不是 print_r() ，我可以执行以下操作（以对其进行测试）...
- 在上次使用的cast语句中使用更具体的类会更好，但我不知道你的类层次结构~Usergroup_Model？
这个答案忽略了与 getDefaultLanguage() 相关的任何事情，因为那不是问题的一部分。
$ITEMS=count($usergroup['groups']); $out=array(); for($i=0; $i<$ITEMS; $i++) { if(isset($usergroup['lang'][$i])) { $out[]=(object)array_merge((array)$usergroup['groups'][$i], (array)$usergroup['lang'][$i]); } else { $out[]=$usergroup['groups'][$i]; } }
回答by Vinod Joshi
if(count($array1) >= count($array2)){
$arr1 = $array1;
$arr2 = $array2;
}else{
$arr1 = $array2;
$arr2 = $array1;
}
$out = array();
foreach ($arr1 as $key => $value){
if(isset($arr2[$key])){
$out[] = array_merge((array)$arr2[$key], (array)$value);
}else{
$out[] = (array)$value;
}
}
pr($out);
