java 将浮点数转换为位
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Convert float to bits
提问by Jan Ajan
How can I get single bits (or an entire variable) of a doubleor a float?
如何获得 adouble或 a 的单个位（或整个变量）float？
For example if I have float a = 0.5;
例如，如果我有 float a = 0.5;
I would expect a Stringequal to:"00111111000000000000000000000000"
我希望String等于："00111111000000000000000000000000"
or in hex:"F000000"
或十六进制："F000000"
回答by Mike Samuel
long bits = Double.doubleToLongBits(myDouble);
System.out.println(Long.toBinaryString(bits));
回答by user949300
Look at Float.floatToIntBits() or Float.floatToRawIntBits(). That gets you the bits as an int. If you need it as a String, Integer.toBinaryString().
看看 Float.floatToIntBits() or Float.floatToRawIntBits()。这会让你得到一个 int 位。如果你需要它作为一个字符串，Integer.toBinaryString().
Note, there may be an issue if the HSB is on - you may need to convert to a long to avoid an "overflow".
请注意，如果 HSB 开启，则可能会出现问题 - 您可能需要转换为 long 以避免“溢出”。
回答by walrider89
public void printFloatBits(float f) {
int bits = Float.floatToIntBits(f);
// Extract each bit from 'bits' and compare it by '0'
for (int i=31; i>=0; --i) {
// int mask = 1 << i;
// int oneBit = bits & mask;
// oneBit == 0 or 1?
System.out.print((bits & (1 << i)) == 0 ? "0" : "1");
}
}
回答by kentcdodds
Double.byteValue()might help you.
Double.byteValue()可能会帮助你。
There is also a 32-bit equivalent Float.byteValue().
还有一个 32 位等效的Float.byteValue().
