java 从 Guava 的 Splitter 创建一个 String[]
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Creating a String[] from Guava's Splitter
提问by slipheed
Is there a more efficient way to create a string array from Guava's Splitterthan the following?
有没有比以下更有效的方法来从Guava 的 Splitter创建字符串数组？
Lists.newArrayList(splitter.split()).toArray(new String[0]);
回答by Philipp Reichart
Probably not so much more efficient, but a lot clearer would be Iterables.toArray(Iterable, Class)
可能效率没有那么高，但会更清晰 Iterables.toArray(Iterable, Class)
This pretty much does what you do already:
这几乎可以完成您已经在做的事情：
public static <T> T[] toArray(Iterable<? extends T> iterable, Class<T> type) {
Collection<? extends T> collection = toCollection(iterable);
T[] array = ObjectArrays.newArray(type, collection.size());
return collection.toArray(array);
}
By using the collection.size()this should even be a tick faster than creating a zero-length array just for the type information and having toArray()create a correctly sized array from that.
通过使用collection.size()this 甚至应该比仅为类型信息创建零长度数组并toArray()从中创建正确大小的数组快一点。
回答by Jason S
How about
怎么样
Iterables.toArray(splitter.split(), String.class);
since there's an Iterables.toArray()method
因为有Iterables.toArray()方法
