Linux 使用 awk 从文本文件中提取数据
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Extracting data from a text file using awk
提问by Graham Bell
Possible Duplicate:
Extract data between two points in a text file
可能的重复：
提取文本文件中两点之间的数据
For example:
例如：
Reply: [200/OK] bytes=29086 time=583ms
I would want to extract the value between "time=" and "ms"
我想提取“time=”和“ms”之间的值
Expected Result:
预期结果：
"583"
“583”
回答by miku
Ugly but works:
丑陋但有效：
$ echo "Reply: [200/OK] bytes=29086 time=583ms" |
awk '{print '} | sed -e 's/[a-z=]//g'
583
Or without sed:
或者没有sed：
$ echo "Reply: [200/OK] bytes=29086 time=583ms" |
awk '{ split(,a,"="); gsub(/ms/,"", a[2]); print a[2] }'
583
回答by shellter
Try this
尝试这个
printf "Reply: [200/OK] bytes=29086 time=583ms\n" \
| awk '/^Reply:/{sub(/^.*time=/,"",echo "Reply: [200/OK] bytes=29086 time=583ms" | sed "s/.*time=\(.*\)ms//"
) ;sub(/ms$/,"",echo "Reply: [200/OK] bytes=29086 time=583ms" | awk -F'time=|ms' '{print }'
); print echo "Reply: [200/OK] bytes=29086 time=583ms" | sed 's/.*time=\([0-9]*\)ms.*//'
}'
I hope this helps.
我希望这有帮助。
P.S. as you appear to be a new user, if you get an answer that helps you please remember to mark it as accepted, and/or give it a + (or -) as a useful answer.
PS，因为您似乎是新用户，如果您得到的答案对您有帮助，请记住将其标记为已接受，和/或给它一个 +（或 -）作为有用的答案。
回答by Paul
回答by Micha? ?rajer
I would use sed for that, but since you ask for awk:
我会使用 sed ，但既然你要求 awk：
##代码##The -Fdefines extended regexp for field separator. So we define that "time=" or "ms" separates the fields, and then print second field.
该-F定义延长字段分隔符的regexp。所以我们定义“time=”或“ms”分隔字段，然后打印第二个字段。
using sed, it would be:
使用 sed，它将是：
##代码##