C# 如何仅从 SaveFileDialog.FileName 获取目录名称
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How to get only directory name from SaveFileDialog.FileName
提问by Redbaron
What would be the easiest way to separate the directory name from the file name when dealing with SaveFileDialog.FileNamein C#?
SaveFileDialog.FileName在 C# 中处理时，将目录名与文件名分开的最简单方法是什么？
采纳答案by Adam Wright
Use:
用：
System.IO.Path.GetDirectoryName(saveDialog.FileName)
(and the corresponding System.IO.Path.GetFileName). The Path class is really rather useful.
（以及相应的System.IO.Path.GetFileName）。Path 类确实相当有用。
回答by rjzii
Since the forward slash is not allowed in the filename, one simple way is to divide the SaveFileDialog.Filename using String.LastIndexOf; for example:
由于文件名中不允许使用正斜杠，一种简单的方法是使用 String.LastIndexOf; 分割 SaveFileDialog.Filename; 例如：
string filename = dialog.Filename;
string path = filename.Substring(0, filename.LastIndexOf("\"));
string file = filename.Substring(filename.LastIndexOf("\") + 1);
回答by Jay Mooney
The Path object in System.IOparses it pretty nicely.
中的 Path 对象System.IO很好地解析了它。
回答by Jake Pearson
You could construct a FileInfo object. It has a Name, FullName, and DirectoryName property.
您可以构造一个 FileInfo 对象。它具有 Name、FullName 和 DirectoryName 属性。
var file = new FileInfo(saveFileDialog.FileName);
Console.WriteLine("File is: " + file.Name);
Console.WriteLine("Directory is: " + file.DirectoryName);
