如何将 number_format 的输出转换回 PHP 中的数字？
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How do I convert output of number_format back to numbers in PHP?
提问by user198729
PHP can't recognize 1,200.00(generated by number_format) but only 1200.00,
PHP 无法识别1,200.00（由 生成number_format），但只能识别1200.00,
What's the general solution for this problem?
这个问题的一般解决方案是什么？
采纳答案by Gumbo
You could remove any character that is not a digit or a decimal point and parse that with floatval:
您可以删除任何不是数字或小数点的字符，然后使用以下命令对其进行解析floatval：
$number = 1200.00;
$parsed = floatval(preg_replace('/[^\d.]/', '', number_format($number)));
var_dump($number === $parsed); // bool(true)
And if the number has not .as decimal point:
如果数字不是.小数点：
function parse_number($number, $dec_point=null) {
if (empty($dec_point)) {
$locale = localeconv();
$dec_point = $locale['decimal_point'];
}
return floatval(str_replace($dec_point, '.', preg_replace('/[^\d'.preg_quote($dec_point).']/', '', $number)));
}
回答by Donnie
If you're using 5.3 or higher (thanks ircmaxell), use numfmt_parse.
如果您使用 5.3 或更高版本（感谢 ircmaxell），请使用numfmt_parse。
回答by Frederic
You can use filter_var. e.g.
您可以使用 filter_var。例如
$num = '1,200,998';
$real_integer = filter_var($num, FILTER_SANITIZE_NUMBER_INT);
echo $real_integer;
will output:
将输出：
1200998
回答by Manuel MT
use ; Sanitize filters
用 ; 消毒过滤器
$number1= '$ 1,989.34';
$number1='$1,989.34';
$number2 = filter_var($number, FILTER_SANITIZE_NUMBER_FLOAT, FILTER_FLAG_ALLOW_FRACTION);//1989.34
$number2 = filter_var($number, FILTER_SANITIZE_NUMBER_FLOAT, FILTER_FLAG_ALLOW_THOUSAND);//1,98934
回答by Shyam
The better way is to use the options in number_formatfunction itself. The format is
更好的方法是使用number_format函数本身的选项。格式是
number_format ( float $number , int $decimals = 0 , string $dec_point = '.' , string $thousands_sep = ',' )
I.e. if you don't need the ','in the formatted string make, it is like
即，如果您不需要','格式化字符串中的 make，就像
$num=23.33333
echo number_format($num,2,'.','');
If you need that as float then typecast the same to float
如果你需要它作为浮动然后将相同的类型转换为浮动
$floatnum= (float) number_format($num,2,'.','');
回答by ircmaxell
You could do $num = (float) str_replace(',', '', $num);Basically, just get rid of the commas, and then cast it as a numeric type (float or int).
你可以做$num = (float) str_replace(',', '', $num);基本上，只需去掉逗号，然后将其转换为数字类型（浮点数或整数）。
回答by birdsaremagic
I use the following code:
我使用以下代码：
function remove_non_numerics($str)
{
$temp = trim($str);
$result = "";
$pattern = '/[^0-9]*/';
$result = preg_replace($pattern, '', $temp);
return $result;
}
回答by Alireza Rahmani Khalili
In this case you can, use PHP roundmethod like: round (12.000000, 2);
在这种情况下，您可以使用 PHPround方法，例如：round (12.000000, 2);
回答by user2598395
use "[^0-9.]+" regex.
使用“[^0-9.]+”正则表达式。
$formattedVal = ',99,999.99';
$unformattedVal = (float)preg_replace("/[^0-9.]+/", "", $formattedVal);
var_dump($unformattedVal);
worked for me.
为我工作。
