Bash：复制+重命名文件夹
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Bash: duplicate + rename folder
提问by Manfredo
Suppose I have a folder named my_folder_oldin /path/to/folder, how can I create a duplicate named my_folder_newin the same directory?
假设我有一个名为my_folder_oldin的文件夹/path/to/folder，如何my_folder_new在同一目录中创建一个重复的文件夹？
EDIT
编辑
Moreover if my_folder_newalready exists, my_folder_oldis created inside the first and not substituted. Why is this happening?
此外，如果my_folder_new已经存在，my_folder_old则在第一个内部创建而不被替换。为什么会这样？
回答by Noproblem
Tutorial copy files, folder link: link
教程复制文件，文件夹链接：链接
Manual cp command : Link
手动 cp 命令：链接
cp -frp /path/to/folder/my_folder_old -T /path/to/folder/my_folder_new
-f, --force
if an existing destination file cannot be opened, remove it
and try again (this option is ignored when the -n option is
also used)
-p same as --preserve=mode,ownership,timestamps
-R, -r, --recursive
copy directories recursively
-T, --no-target-directory
treat DEST as a normal file
Though if my_folder_new already exists, my_folder_old is created inside the first and not substituted. Why is this happening?
尽管如果 my_folder_new 已经存在，则 my_folder_old 是在第一个内部创建的而不是被替换的。为什么会这样？
The reason why is this happening because, my_folder_new already created. Doing same cp command it will see as new path, /path/to/folder/my_folder_new/
之所以会发生这种情况，是因为 my_folder_new 已经创建。执行相同的 cp 命令，它将看到新路径，/path/to/folder/my_folder_new/
