Java 如何在任何语言的整数中的特定位置翻转位
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how to flip a bit at a specific position in an integer in any language
提问by
I have an integer n, and I want to flip its kth bit (from the lowest) in its binary representation. How can I do it?
我有一个 integer n，我想k在其二进制表示中翻转它的第 th 位（从最低位）。我该怎么做？
For example, if I have n=0b01101and k=2, then the result is 0b01001=9
例如，如果我有n=0b01101and k=2，那么结果是0b01001=9
Any language is fine. Thank you.
任何语言都可以。谢谢你。
回答by NPE
To flip one or more bits, use binary XOR. In your case, the appropriate XOR mask is 1shiftedkbits to the left.
要翻转一位或多位，请使用二进制 XOR。在您的情况下，适当的 XOR 掩码向左1移位k。
In Python:
在 Python 中：
In [58]: 0b01101 ^ (1 << 2)
Out[58]: 9
The expression:
表达方式：
n ^ (1 << k)
is valid in C, Java, Python and a few other languages (provided the variables are appropriately defined).
在 C、Java、Python 和一些其他语言中有效（前提是变量被适当地定义）。
回答by Kevin
Here's how you'd do it in C:
下面是你在 C 中的做法：
n ^ (1 << k)
回答by Constablebrew
Left-shift the number 1 the number of digits you need, and then XOR the number.
将数字 1 左移所需的位数，然后对数字进行异或。
JavaScript:
JavaScript：
var num = 6, k = 2;
num = num ^ (1 << k);
What is happening:
怎么了：
num = 0b01101 XOR (0b00001 << 2)
num = 0b01101 XOR 0b00100
num = 0b01001
回答by Ion
In c you just do this to toggle it:
在 c 中，您只需执行以下操作即可切换它：
n ^= 1 << k;
but there are other ways of doing it like:
但还有其他方法可以做到：
n |= ( 1 << k);
This shifts bit k to 1
这将位 k 移至 1
Now if you want to flip the bit you can do an if statement with a unary and to see how you need to flip it
现在如果你想翻转位，你可以用一元做一个 if 语句，看看你需要如何翻转它
number = pow(2,k)
if((number & n) != number)
//this means that it's a 0 at position k
n |= ( 1 << k);
else
//this means that it's a 1 at position k
n &= ( 0 << k);
