创建一个java程序来显示一个数字的倍数
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Create a java program to display multiples of a number
提问by Kyle
I'm trying to Write the main method of a Java program that has the user enter two integers, i and n. If either integer is less than 2, output “Please enter numbers above 1.” Otherwise, output the n positive multiples of i, separated by spaces.
我正在尝试编写一个让用户输入两个整数 i 和 n 的 Java 程序的主要方法。如果任一整数小于 2，则输出“请输入大于 1 的数字”。否则，输出 i 的 n 个正倍数，以空格分隔。
I'm close but can't figure out how to do display the multiples.
我很接近，但不知道如何显示倍数。
Here's what a sample run should look like:
以下是示例运行的样子：
Enter i: 4
输入我：4
Enter n: 6
输入 n：6
6 multiples of 4 are: 8 12 16 20 24 28
4 的 6 倍数是：8 12 16 20 24 28
import java.util.*;
public class HW5Problem3 {
public static void main (String [] args) {
int i = 0;
int n = 0;
Scanner input = new Scanner(System.in);
System.out.print("Enter i: ");
i = input.nextInt();
System.out.print("Enter n: ");
n = input.nextInt();
if ((i <= 1) || (n <= 1)) {
System.out.println("Please enter numbers above 1");
System.exit(1);
}
System.out.print(n + " multiples of " + i + " are: ");
}
}
采纳答案by Cedric Achi
import java.util.Scanner;
public static void main(String[] args){
Scanner input = new Scanner(System.in);
int i = 0;
int n = 0;
//It's use to verify the inputs (i and n).
do{
System.out.print("Enter i :");
i = input.nextInt();
System.out.print("\nEnter n :");
n = input.nextInt();
if(i >= 1 || n <= 1){
System.out.println("Please enter numbers above 1 \n");
}
}while(i <= 1 || n <= 1);
System.out.print(n + " multiples of " + i + " are: ");
for (int counter = 0 ; counter < n ; counter++) {
System.out.print(i*(2 + counter) + " ");
}
}
回答by Paul Ostrowski
You'll need to create a loop (for loop or while loop) to iterate from 2 to n+1, and multiply i by your loop variable, outputting each value inside the loop
您需要创建一个循环（for 循环或 while 循环）以从 2 迭代到 n+1，并将 i 乘以循环变量，输出循环内的每个值
回答by Würgspa?
nis the multiplier, iis the factor, right? In programming the multiplier is the loop maximum:
n是乘数，i是因数，对吗？在编程中，乘数是循环最大值：
System.out.print(n + " multiples of " + i + " are: ");
for (int inc=1; inc<=n; inc++) {
System.out.print(" " + i*inc);
}
This prints out: 4 8 12 16 20 24
这打印出来：4 8 12 16 20 24
If you really want to have this as output: 8 12 16 20 24 28 copy/paste this line:
如果你真的想把它作为输出： 8 12 16 20 24 28 复制/粘贴这一行：
for (int inc=2; inc<=(n+1); inc++)
回答by sherl
U can use following method in that class
您可以在该类中使用以下方法
public static void mult(int i,int n){
int[] arr=new int[n];
int count=2;
for(int x=0;x<n;x++){
arr[x]=i*count++;
}
for(int y=0;y<arr.length;y++){
System.out.print(arr[y]+" ");
}
}
and now your final code looks like
现在你的最终代码看起来像
import java.util.*;
public class HW5Problem3 {
private int i = 0;
private int n = 0;
public static void main(String[] args) {
int i = 0;
int n = 0;
Scanner input = new Scanner(System.in);
System.out.print("Enter i: ");
i = input.nextInt();
System.out.print("Enter n: ");
n = input.nextInt();
if ((i <= 1) || (n <= 1)) {
System.out.println("Please enter numbers above 1");
System.exit(1);
} else {
System.out.print(n + " multiples of " + i + " are: ");
mult(i, n);
}
}
public static void mult(int i, int n) {
int[] arr = new int[n];
int count = 2;
for (int x = 0; x < n; x++) {
arr[x] = i * count++;
}
for (int y = 0; y < arr.length; y++) {
System.out.print(arr[y] + " ");
}
}
}
