在java中将字符转换为ASCII数值
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Convert character to ASCII numeric value in java
提问by Celta
I have String name = "admin";
then I do String char = name.substring(0,1); //char="a"
我有String name = "admin";
然后我做String char = name.substring(0,1); //char="a"
I want to convert the charto its ASCII value (97), how can I do this in java?
我想将 转换char为它的 ASCII 值 (97)，我该如何在 java 中做到这一点？
采纳答案by SudoRahul
Very simple. Just cast your charas an int.
很简单。只需将您char作为int.
char character = 'a';
int ascii = (int) character;
In your case, you need to get the specific Character from the String first and then cast it.
在您的情况下，您需要先从字符串中获取特定的字符，然后再进行转换。
char character = name.charAt(0); // This gives the character 'a'
int ascii = (int) character; // ascii is now 97.
Though cast is not required explicitly, but its improves readability.
虽然没有明确要求强制转换，但它提高了可读性。
int ascii = character; // Even this will do the trick.
回答by Daniel Lerps
Just cast the char to an int.
只需将字符转换为整数。
char character = 'a';
int number = (int) character;
The value of numberwill be 97.
的值为number97。
回答by christopher
Instead of this:
取而代之的是：
String char = name.substring(0,1); //char="a"
You should use the charAt()method.
您应该使用该charAt()方法。
char c = name.charAt(0); // c='a'
int ascii = (int)c;
回答by Vineet Singla
Convert the char to int.
将字符转换为整数。
String name = "admin";
int ascii = name.toCharArray()[0];
Also :
还 ：
int ascii = name.charAt(0);
回答by Ricardo Cacheira
It's simple, get the character you want, and convert it to int.
很简单，得到你想要的字符，然后转换成int。
String name = "admin";
int ascii = name.charAt(0);
回答by user1721904
If you wanted to convert the entire string into concatenated ASCII values then you can use this -
如果您想将整个字符串转换为连接的 ASCII 值，那么您可以使用这个 -
String str = "abc"; // or anything else
StringBuilder sb = new StringBuilder();
for (char c : str.toCharArray())
sb.append((int)c);
BigInteger mInt = new BigInteger(sb.toString());
System.out.println(mInt);
wherein you will get 979899 as output.
其中您将获得 979899 作为输出。
Credit to this.
归功于此。
I just copied it here so that it would be convenient for others.
我只是把它复制到这里，以便其他人方便。
回答by stinepike
just a different approach
只是一种不同的方法
String s = "admin";
byte[] bytes = s.getBytes("US-ASCII");
bytes[0]will represent ascii of a.. and thus the other characters in the whole array.
bytes[0]将代表 a.. 的 ascii，从而代表整个数组中的其他字符。
回答by Sandeepp Sah
String str = "abc"; // or anything else
// Stores strings of integer representations in sequence
StringBuilder sb = new StringBuilder();
for (char c : str.toCharArray())
sb.append((int)c);
// store ascii integer string array in large integer
BigInteger mInt = new BigInteger(sb.toString());
System.out.println(mInt);
回答by Sandeepp Sah
I know this has already been answered in several forms but here is my bit of code with a look to go through all the characters.
我知道这已经以多种形式得到了回答，但这是我的一些代码，用于查看所有字符。
Here is the code, started with the class
这是代码，从类开始
public class CheckChValue { // Class name
public static void main(String[] args) { // class main
String name = "admin"; // String to check it's value
int nameLenght = name.length(); // length of the string used for the loop
for(int i = 0; i < nameLenght ; i++){ // while counting characters if less than the length add one
char character = name.charAt(i); // start on the first character
int ascii = (int) character; //convert the first character
System.out.println(character+" = "+ ascii); // print the character and it's value in ascii
}
}
}
}
回答by Raúl Vela
You can check the ASCII′s number with this code.
您可以使用此代码检查 ASCII 的编号。
String name = "admin";
char a1 = a.charAt(0);
int a2 = a1;
System.out.println("The number is : "+a2); // the value is 97
If I am wrong, apologies.
如果我错了，道歉。
