php Slim - 如何使用“Content-Type: application/json”标头发送响应？
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Slim - How to send response with "Content-Type: application/json" header?
提问by branquito
I have this simple REST api, done in Slim,
我有这个简单的 REST api，在 Slim 中完成，
<?php
require '../vendor/autoload.php';
function getDB()
{
$dsn = 'sqlite:/home/branchito/personal-projects/slim3-REST/database.sqlite3';
$options = array(
PDO::ATTR_PERSISTENT => true,
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION
);
try {
$dbh = new PDO($dsn);
foreach ($options as $k => $v)
$dbh->setAttribute($k, $v);
return $dbh;
}
catch (PDOException $e) {
$error = $e->getMessage();
}
}
$app = new \Slim\App();
$app->get('/', function($request, $response) {
$response->write('Bienvenidos a Slim 3 API');
return $response;
});
$app->get('/getScore/{id:\d+}', function($request, $response, $args) {
try {
$db = getDB();
$stmt = $db->prepare("SELECT * FROM students
WHERE student_id = :id
");
$stmt->bindParam(':id', $args['id'], PDO::PARAM_INT);
$stmt->execute();
$student = $stmt->fetch(PDO::FETCH_OBJ);
if($student) {
$response->withHeader('Content-Type', 'application/json');
$response->write(json_encode($student));
} else { throw new PDOException('No records found');}
} catch (PDOException $e) {
$response->withStatus(404);
$err = '{"error": {"text": "'.$e->getMessage().'"}}';
$response->write($err);
}
return $response;
});
$app->run();
however, I can't get browser to send me application/jsoncontent type, it
always sends text/html? What I am doing wrong?
但是，我无法让浏览器向我发送application/json内容类型，它总是发送text/html? 我做错了什么？
EDIT:
编辑：
Ok, after two hours of hitting the head against the wall, I stumbled upon this answer:
好吧，在用头撞墙两个小时后，我偶然发现了这个答案：
https://github.com/slimphp/Slim/issues/1535(at the bottom of a page)
which explains what happens, appears that responseobject is immutable and
as such it must be returned or reassigned if you want to return it after
while.
https://github.com/slimphp/Slim/issues/1535（在页面底部）解释了发生的情况，似乎该response对象是不可变的，因此如果您想在一段时间后返回它，则必须返回或重新分配它.
回答by branquito
So, instead of this:
所以，而不是这个：
if($student) {
$response->withHeader('Content-Type', 'application/json');
$response->write(json_encode($student));
return $response;
} else { throw new PDOException('No records found');}
Do like this:
这样做：
if($student) {
return $response->withStatus(200)
->withHeader('Content-Type', 'application/json')
->write(json_encode($student));
} else { throw new PDOException('No records found');}
And all is well and good.
一切都很好。
回答by conrad10781
For V3, withJson()is available.
对于 V3，withJson()可用。
So you can do something like:
因此，您可以执行以下操作：
return $response->withStatus(200)
->withJson(array($request->getAttribute("route")
->getArgument("someParameter")));
Note:Make sure you return the $responsebecause if you forget, the response will still come out but it will not be application/json.
注意：确保您返回 ，$response因为如果您忘记了，响应仍然会出现，但不会是application/json。
回答by benyafai
For V3, the simplest method as per the Slim docsis:
对于 V3，根据Slim 文档，最简单的方法是：
$data = array('name' => 'Rob', 'age' => 40);
return $response->withJson($data, 201);
This automatically sets the Content-Type to application/json;charset=utf-8and lets you set a HTTP status code too (defaults to 200 if omitted).
这会自动将 Content-Typeapplication/json;charset=utf-8设置为并让您也设置 HTTP 状态代码（如果省略，则默认为 200）。
回答by jcubic
You can also use:
您还可以使用：
$response = $response->withHeader('Content-Type', 'application/json');
$response->write(json_encode($student));
return $response;
because withHeaderreturn new response object. That way you have more then one write and code between.
因为withHeader返回新的响应对象。这样一来，您就可以进行多次编写和编写代码。
