是否有 Porter2 词干分析器的 java 实现

声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow 原文地址: http://stackoverflow.com/questions/4397107/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me): StackOverFlow

提示:将鼠标放在中文语句上可以显示对应的英文。显示中英文
时间:2020-10-30 06:11:52  来源:igfitidea点击:

Is there a java implementation of Porter2 stemmer

javaporter-stemmersnowball

提问by bikashg

Do you know any java implementation of the Porter2 stemmer(or any better stemmer written in java)? I know that there is a java version of Porter(not Porter2) here :

你知道 Porter2 词干分析器的任何 java 实现(或任何用 java 编写的更好的词干分析器)吗?我知道这里有一个 Java 版本的 Porter(不是 Porter2):

http://tartarus.org/~martin/PorterStemmer/java.txt

http://tartarus.org/~martin/PorterStemmer/java.txt

but on http://tartarus.org/~martin/PorterStemmer/the author mentions that the Porter is bit outdated and recommends to use Porter2, available at

但在http://tartarus.org/~martin/PorterStemmer/ 上,作者提到 Porter 有点过时,建议使用 Porter2,可在

http://snowball.tartarus.org/algorithms/english/stemmer.html

http://snowball.tartarus.org/algorithms/english/stemmer.html

However, the problem with me is that this Porter2 is written in snowball(I never heard of it before, so don't know anything about it). What I am exactly looking for is a java version of it.

然而,我的问题是这个 Porter2 是用滚雪球写的(我以前从未听说过,所以对它一无所知)。我正在寻找的是它的 Java 版本。

Thanks. Your help will he highly appreciated.

谢谢。您的帮助将得到他的高度赞赏。

回答by Joel

The Snowball algo is available as a Java download

Snowball 算法可用作Java 下载

And from snowball.tartarus.org:

来自snowball.tartarus.org

Feb 2002 - Java support Richard has modified the snowball code generator to produce Java output as well as ANSI C output. This means that pure Java systems can now use the snowball stemmers.

2002 年 2 月 - Java 支持 Richard 修改了滚雪球代码生成器以生成 Java 输出和 ANSI C 输出。这意味着纯 Java 系统现在可以使用滚雪球词干分析器。

This is what you want, right?

这就是你想要的,对吧?

You can create an instance of it like so:

您可以像这样创建它的实例:

  Class stemClass = Class.forName("org.tartarus.snowball.ext." + lang + "Stemmer");
  stemmer = (SnowballProgram) stemClass.newInstance();
  stemmer.setCurrent("your_word");
  stemmer.stem();
  String your_stemmed_word = stemmer.getCurrent();  

回答by Raja

/*

   Porter stemmer in Java. The original paper is in

       Porter, 1980, An algorithm for suffix stripping, Program, Vol. 14,
       no. 3, pp 130-137,

   See also http://www.tartarus.org/~martin/PorterStemmer

   History:

   Release 1

   Bug 1 (reported by Gonzalo Parra 16/10/99) fixed as marked below.
   The words 'aed', 'eed', 'oed' leave k at 'a' for step 3, and b[k-1]
   is then out outside the bounds of b.

   Release 2

   Similarly,

   Bug 2 (reported by Steve Dyrdahl 22/2/00) fixed as marked below.
   'ion' by itself leaves j = -1 in the test for 'ion' in step 5, and
   b[j] is then outside the bounds of b.

   Release 3

   Considerably revised 4/9/00 in the light of many helpful suggestions
   from Brian Goetz of Quiotix Corporation ([email protected]).

   Release 4

*/

import java.io.*;

/**
  * Stemmer, implementing the Porter Stemming Algorithm
  *
  * The Stemmer class transforms a word into its root form.  The input
  * word can be provided a character at time (by calling add()), or at once
  * by calling one of the various stem(something) methods.
  */

class Stemmer
{  private char[] b;
   private int i,     /* offset into b */
               i_end, /* offset to end of stemmed word */
               j, k;
   private static final int INC = 50;
                     /* unit of size whereby b is increased */
   public Stemmer()
   {  b = new char[INC];
      i = 0;
      i_end = 0;
   }

   /**
    * Add a character to the word being stemmed.  When you are finished
    * adding characters, you can call stem(void) to stem the word.
    */

   public void add(char ch)
   {  if (i == b.length)
      {  char[] new_b = new char[i+INC];
         for (int c = 0; c < i; c++) new_b[c] = b[c];
         b = new_b;
      }
      b[i++] = ch;
   }


   /** Adds wLen characters to the word being stemmed contained in a portion
    * of a char[] array. This is like repeated calls of add(char ch), but
    * faster.
    */

   public void add(char[] w, int wLen)
   {  if (i+wLen >= b.length)
      {  char[] new_b = new char[i+wLen+INC];
         for (int c = 0; c < i; c++) new_b[c] = b[c];
         b = new_b;
      }
      for (int c = 0; c < wLen; c++) b[i++] = w[c];
   }

   /**
    * After a word has been stemmed, it can be retrieved by toString(),
    * or a reference to the internal buffer can be retrieved by getResultBuffer
    * and getResultLength (which is generally more efficient.)
    */
   public String toString() { return new String(b,0,i_end); }

   /**
    * Returns the length of the word resulting from the stemming process.
    */
   public int getResultLength() { return i_end; }

   /**
    * Returns a reference to a character buffer containing the results of
    * the stemming process.  You also need to consult getResultLength()
    * to determine the length of the result.
    */
   public char[] getResultBuffer() { return b; }

   /* cons(i) is true <=> b[i] is a consonant. */

   private final boolean cons(int i)
   {  switch (b[i])
      {  case 'a': case 'e': case 'i': case 'o': case 'u': return false;
         case 'y': return (i==0) ? true : !cons(i-1);
         default: return true;
      }
   }

   /* m() measures the number of consonant sequences between 0 and j. if c is
      a consonant sequence and v a vowel sequence, and <..> indicates arbitrary
      presence,

         <c><v>       gives 0
         <c>vc<v>     gives 1
         <c>vcvc<v>   gives 2
         <c>vcvcvc<v> gives 3
         ....
   */

   private final int m()
   {  int n = 0;
      int i = 0;
      while(true)
      {  if (i > j) return n;
         if (! cons(i)) break; i++;
      }
      i++;
      while(true)
      {  while(true)
         {  if (i > j) return n;
               if (cons(i)) break;
               i++;
         }
         i++;
         n++;
         while(true)
         {  if (i > j) return n;
            if (! cons(i)) break;
            i++;
         }
         i++;
       }
   }

   /* vowelinstem() is true <=> 0,...j contains a vowel */

   private final boolean vowelinstem()
   {  int i; for (i = 0; i <= j; i++) if (! cons(i)) return true;
      return false;
   }

   /* doublec(j) is true <=> j,(j-1) contain a double consonant. */

   private final boolean doublec(int j)
   {  if (j < 1) return false;
      if (b[j] != b[j-1]) return false;
      return cons(j);
   }

   /* cvc(i) is true <=> i-2,i-1,i has the form consonant - vowel - consonant
      and also if the second c is not w,x or y. this is used when trying to
      restore an e at the end of a short word. e.g.

         cav(e), lov(e), hop(e), crim(e), but
         snow, box, tray.

   */

   private final boolean cvc(int i)
   {  if (i < 2 || !cons(i) || cons(i-1) || !cons(i-2)) return false;
      {  int ch = b[i];
         if (ch == 'w' || ch == 'x' || ch == 'y') return false;
      }
      return true;
   }

   private final boolean ends(String s)
   {  int l = s.length();
      int o = k-l+1;
      if (o < 0) return false;
      for (int i = 0; i < l; i++) if (b[o+i] != s.charAt(i)) return false;
      j = k-l;
      return true;
   }

   /* setto(s) sets (j+1),...k to the characters in the string s, readjusting
      k. */

   private final void setto(String s)
   {  int l = s.length();
      int o = j+1;
      for (int i = 0; i < l; i++) b[o+i] = s.charAt(i);
      k = j+l;
   }

   /* r(s) is used further down. */

   private final void r(String s) { if (m() > 0) setto(s); }

   /* step1() gets rid of plurals and -ed or -ing. e.g.

          caresses  ->  caress
          ponies    ->  poni
          ties      ->  ti
          caress    ->  caress
          cats      ->  cat

          feed      ->  feed
          agreed    ->  agree
          disabled  ->  disable

          matting   ->  mat
          mating    ->  mate
          meeting   ->  meet
          milling   ->  mill
          messing   ->  mess

          meetings  ->  meet

   */

   private final void step1()
   {  if (b[k] == 's')
      {  if (ends("sses")) k -= 2; else
         if (ends("ies")) setto("i"); else
         if (b[k-1] != 's') k--;
      }
      if (ends("eed")) { if (m() > 0) k--; } else
      if ((ends("ed") || ends("ing")) && vowelinstem())
      {  k = j;
         if (ends("at")) setto("ate"); else
         if (ends("bl")) setto("ble"); else
         if (ends("iz")) setto("ize"); else
         if (doublec(k))
         {  k--;
            {  int ch = b[k];
               if (ch == 'l' || ch == 's' || ch == 'z') k++;
            }
         }
         else if (m() == 1 && cvc(k)) setto("e");
     }
   }

   /* step2() turns terminal y to i when there is another vowel in the stem. */

   private final void step2() { if (ends("y") && vowelinstem()) b[k] = 'i'; }

   /* step3() maps double suffices to single ones. so -ization ( = -ize plus
      -ation) maps to -ize etc. note that the string before the suffix must give
      m() > 0. */

   private final void step3() { if (k == 0) return; /* For Bug 1 */ switch (b[k-1])
   {
       case 'a': if (ends("ational")) { r("ate"); break; }
                 if (ends("tional")) { r("tion"); break; }
                 break;
       case 'c': if (ends("enci")) { r("ence"); break; }
                 if (ends("anci")) { r("ance"); break; }
                 break;
       case 'e': if (ends("izer")) { r("ize"); break; }
                 break;
       case 'l': if (ends("bli")) { r("ble"); break; }
                 if (ends("alli")) { r("al"); break; }
                 if (ends("entli")) { r("ent"); break; }
                 if (ends("eli")) { r("e"); break; }
                 if (ends("ousli")) { r("ous"); break; }
                 break;
       case 'o': if (ends("ization")) { r("ize"); break; }
                 if (ends("ation")) { r("ate"); break; }
                 if (ends("ator")) { r("ate"); break; }
                 break;
       case 's': if (ends("alism")) { r("al"); break; }
                 if (ends("iveness")) { r("ive"); break; }
                 if (ends("fulness")) { r("ful"); break; }
                 if (ends("ousness")) { r("ous"); break; }
                 break;
       case 't': if (ends("aliti")) { r("al"); break; }
                 if (ends("iviti")) { r("ive"); break; }
                 if (ends("biliti")) { r("ble"); break; }
                 break;
       case 'g': if (ends("logi")) { r("log"); break; }
   } }

   /* step4() deals with -ic-, -full, -ness etc. similar strategy to step3. */

   private final void step4() { switch (b[k])
   {
       case 'e': if (ends("icate")) { r("ic"); break; }
                 if (ends("ative")) { r(""); break; }
                 if (ends("alize")) { r("al"); break; }
                 break;
       case 'i': if (ends("iciti")) { r("ic"); break; }
                 break;
       case 'l': if (ends("ical")) { r("ic"); break; }
                 if (ends("ful")) { r(""); break; }
                 break;
       case 's': if (ends("ness")) { r(""); break; }
                 break;
   } }

   /* step5() takes off -ant, -ence etc., in context <c>vcvc<v>. */

   private final void step5()
   {   if (k == 0) return; /* for Bug 1 */ switch (b[k-1])
       {  case 'a': if (ends("al")) break; return;
          case 'c': if (ends("ance")) break;
                    if (ends("ence")) break; return;
          case 'e': if (ends("er")) break; return;
          case 'i': if (ends("ic")) break; return;
          case 'l': if (ends("able")) break;
                    if (ends("ible")) break; return;
          case 'n': if (ends("ant")) break;
                    if (ends("ement")) break;
                    if (ends("ment")) break;
                    /* element etc. not stripped before the m */
                    if (ends("ent")) break; return;
          case 'o': if (ends("ion") && j >= 0 && (b[j] == 's' || b[j] == 't')) break;
                                    /* j >= 0 fixes Bug 2 */
                    if (ends("ou")) break; return;
                    /* takes care of -ous */
          case 's': if (ends("ism")) break; return;
          case 't': if (ends("ate")) break;
                    if (ends("iti")) break; return;
          case 'u': if (ends("ous")) break; return;
          case 'v': if (ends("ive")) break; return;
          case 'z': if (ends("ize")) break; return;
          default: return;
       }
       if (m() > 1) k = j;
   }

   /* step6() removes a final -e if m() > 1. */

   private final void step6()
   {  j = k;
      if (b[k] == 'e')
      {  int a = m();
         if (a > 1 || a == 1 && !cvc(k-1)) k--;
      }
      if (b[k] == 'l' && doublec(k) && m() > 1) k--;
   }

   /** Stem the word placed into the Stemmer buffer through calls to add().
    * Returns true if the stemming process resulted in a word different
    * from the input.  You can retrieve the result with
    * getResultLength()/getResultBuffer() or toString().
    */
   public void stem()
   {  k = i - 1;
      if (k > 1) { step1(); step2(); step3(); step4(); step5(); step6(); }
      i_end = k+1; i = 0;
   }

   /** Test program for demonstrating the Stemmer.  It reads text from a
    * a list of files, stems each word, and writes the result to standard
    * output. Note that the word stemmed is expected to be in lower case:
    * forcing lower case must be done outside the Stemmer class.
    * Usage: Stemmer file-name file-name ...
    */
   public static void main(String[] args)
   {
      char[] w = new char[501];
      Stemmer s = new Stemmer();
      for (int i = 0; i < args.length; i++)
      try
      {
         FileInputStream in = new FileInputStream(args[i]);

         try
         { while(true)

           {  int ch = in.read();
              if (Character.isLetter((char) ch))
              {
                 int j = 0;
                 while(true)
                 {  ch = Character.toLowerCase((char) ch);
                    w[j] = (char) ch;
                    if (j < 500) j++;
                    ch = in.read();
                    if (!Character.isLetter((char) ch))
                    {
                       /* to test add(char ch) */
                       for (int c = 0; c < j; c++) s.add(w[c]);

                       /* or, to test add(char[] w, int j) */
                       /* s.add(w, j); */

                       s.stem();
                       {  String u;

                          /* and now, to test toString() : */
                          u = s.toString();

                          /* to test getResultBuffer(), getResultLength() : */
                          /* u = new String(s.getResultBuffer(), 0, s.getResultLength()); */

                          System.out.print(u);
                       }
                       break;
                    }
                 }
              }
              if (ch < 0) break;
              System.out.print((char)ch);
           }
         }
         catch (IOException e)
         {  System.out.println("error reading " + args[i]);
            break;
         }
      }
      catch (FileNotFoundException e)
      {  System.out.println("file " + args[i] + " not found");
         break;
      }
   }
}

回答by athena

It is available as a part of MG4J.

它可作为MG4J的一部分使用

See the documentation for EnglishStemmer, i.e. Porter2. Use method processTerm(MutableString ms)

请参阅文件EnglishStemmer,即Porter2。使用方法processTerm(MutableString ms)

MG4J also gives you java versions of other stemmers. See the snowball package. All these stemmers can be used independently.

MG4J 还为您提供了其他词干分析器的 Java 版本。请参阅滚雪球包。所有这些词干分析器都可以独立使用。

回答by girip11

The following link contains snowball stemmer api.It has the porter stemmer2 implementation. http://preciselyconcise.com/apis_and_installations/snowball_stemmer.php

以下链接包含滚雪球茎干 api。它具有 porter stemmer2 实现。 http://preciselyconcise.com/apis_and_installations/snowball_stemmer.php

回答by peter.murray.rust

Maybe not a direct answer, but there are stemmers in many NLP toolkits - see http://en.wikipedia.org/wiki/Natural_language_processing_toolkits. There's a related question here Tokenizer, Stop Word Removal, Stemming in Javawith several answers that might be useful.

也许不是直接的答案,但许多 NLP 工具包中都有词干分析器 - 请参阅http://en.wikipedia.org/wiki/Natural_language_processing_toolkits。这里有一个相关的问题Tokenizer, Stop Word Removal, Stemming in Java有几个可能有用的答案。

We use OpenNLPwhich is written in Java and may provide the functionality. I wouldn't expect the variation between stemmers to be critical if you are working in English.

我们使用用 Java 编写的OpenNLP并可能提供该功能。如果您使用英语工作,我不认为词干分析器之间的差异至关重要。

回答by Riduidel

Seems like Luceneintegrates, in one form or another, some stemming algorithms. You may find what you're looking for starting at package org.apache.lucene.analysis. I however fear the stemming code to be deeply integrated into analysis components, making as a consequence quite hard its extraction ...

似乎Lucene以一种或另一种形式集成了一些词干算法。您可能会从 package 开始找到您要找的东西org.apache.lucene.analysis。然而,我担心词干代码会深入集成到分析组件中,因此很难提取......

回答by schmmd