php 如何在此日期时间字符串的时间上添加一个小时?
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How to add an hour onto the time of this datetime string?
提问by Hard worker
Here's an example of the datetime strings I am working with:
这是我正在使用的日期时间字符串的示例:
Tue May 15 10:14:30 +0000 2012
Here is my attempt to add an hour onto it:
这是我尝试在上面增加一个小时的尝试:
$time = 'Tue May 15 10:14:30 +0000 2012';
$dt = new DateTime($time);
$dt->add(new DateInterval('P1h'));
But the second line gives the error that it couldn't be converted.
但是第二行给出了无法转换的错误。
Thanks.
谢谢。
回答by Jon
You should add a Tbefore the time specification part:
您应该T在时间规范部分之前添加一个:
$time = 'Tue May 15 10:14:30 +0000 2012';
$dt = new DateTime($time);
$dt->add(new DateInterval('PT1H'));
See the DateIntervalconstructordocumentation:
请参阅DateInterval构造函数文档:
The format starts with the letter P, for "period." Each duration period is represented by an integer value followed by a period designator. If the duration contains time elements, that portion of the specification is preceded by the letter T.
格式以字母 P 开头,表示“句点”。每个持续时间段由一个整数值表示,后跟一个时间段指示符。如果持续时间包含时间元素,则规范的该部分前面有字母 T。
(Emphasis added)
(强调)
回答by Marino Linaje
Previous answers work. However, I usually use datetime modify in my externally hosted websites. Check php manualfor more information. With the code proposed, it should work like this:
以前的答案有效。但是,我通常在外部托管的网站中使用日期时间修改。查看php 手册以获取更多信息。使用建议的代码,它应该像这样工作:
$time = 'Tue May 15 10:14:30 +0000 2012';
$dt = new DateTime($time);
$dt->modify('+ 1 hour');
For those not using object orientation, just use it this way (first line DateTime just to bring somethng new to this thread, I use it to check server time):
对于那些不使用面向对象的人,就这样使用它(第一行 DateTime 只是为了给这个线程带来一些新的东西,我用它来检查服务器时间):
$dt = new DateTime("@".$_SERVER['REQUEST_TIME']); // convert UNIX epoch to PHP DateTime
$dt = date_modify($dt, "+1 hour");
Best,
最好的事物,
回答by lorenzo-s
Using strtotime():
使用strtotime():
$time = 'Tue May 15 10:14:30 +0000 2012';
$time = strtotime($time) + 3600; // Add 1 hour
$time = date('D M j G:i:s O Y', $time); // Back to string
echo $time;

