javascript 在 jQuery 的 Deferred 对象中抛出错误
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Throwing an Error in jQuery's Deferred object
提问by Bergi
I have an $.ajaxpromise and want to check whether my (syntactically valid) response contains an error, triggering the rejected status in that case.
我有一个$.ajax承诺，想检查我的（语法上有效的）响应是否包含错误，在这种情况下触发拒绝状态。
I have worked with my own promise library which deals such tasks easily. I do not really like jQuery's Promise(cache) implementation with its Deferredobjectand may have overlooked something, because I seldom use it. I think the way to go is just using .then(), which seems to be rather complicated:
我使用过自己的 Promise 库，可以轻松处理此类任务。我不太喜欢 jQuery 的Promise( cache) 实现及其Deferred对象，并且可能忽略了一些东西，因为我很少使用它。我认为要走的路只是使用.then()，这似乎相当复杂：
return $.ajax(...).then(function success(response) {
var problem = hasError(response);
if (problem) {
var error = new $.Deferred;
error.reject(problem);
return error;
} else
return response;
});
This should return a promise which is rejected in case of network errors or problems with the response. But is returning a rejected deferred really the [only|best|shortest] way to go?
这应该返回一个承诺，在网络错误或响应问题的情况下被拒绝。但是返回一个被拒绝的 deferred 真的是 [only|best|shortest] 方法吗？
I also would appriciate help on how to deal with such "error-throwing response handlers" in the ajax options themselfes, I could not find good documentation about them.
我也会在如何处理 ajax 选项本身中的此类“错误抛出响应处理程序”方面提供帮助，但我找不到关于它们的良好文档。
Disclaimer: No, I cant change the server responses. The problem-detecting method is synchronous. I don't want to use other libraries, I'm particularly interested in the way jQuery solves this.
免责声明：不，我无法更改服务器响应。问题检测方法是同步的。我不想使用其他库，我对 jQuery 解决这个问题的方式特别感兴趣。
回答by Eli
Now updated for jQuery 1.8+
现在为 jQuery 1.8+ 更新
The easiest way to tackle this is to run the response of $.ajaxthrough .thento filter based on success or failure of the data.
解决这个最简单的方法是运行的响应$.ajax，通过.then基于数据的成功或失败的过滤器。
$.ajax()
.then(function (response) {
return $.Deferred(function (deferred) {
var problem = hasError(response);
if (problem) {
return deferred.reject(problem)
}
deferred.resolve(response);
}).promise();
});
You could then return this new promise to whatever calling code would consume this:
然后，您可以将这个新承诺返回给任何调用代码会使用它：
var request = function () {
return $.ajax()
.then(function (response) {
return $.Deferred(function (deferred) {
var problem = hasError(response);
if (problem) {
return deferred.reject(problem)
}
deferred.resolve(response);
}).promise();
});
};
request()
.done(function (response) {
// handle success
})
.fail(function (problem) {
// handle failure
});
