jQuery 基本表单验证如果或

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时间:2020-08-26 17:51:48  来源:igfitidea点击:

jQuery basic form validation if or

jqueryif-statementvalidation

提问by benhowdle89

this is not working and i cant really see anything wrong with it, looks straightforward enough:

这不起作用,我真的看不出它有什么问题,看起来很简单:

            $("#formLogin").submit(function(){
                var username = $("#username").val();
                var password = $("#password").val();
                if (username == ' ' || password == ' '){
                    return false;
                }
                else return true;
            });

EDIT:

编辑:

Its still submitting the form even if the fields are empty

即使字段为空,它仍在提交表单

回答by Vincent Ramdhanie

Are you trying to detect blank usernames and passwords?

您是否正在尝试检测空白用户名和密码?

  $("#formLogin").submit(function(){
            var username = $("#username").val();
            var password = $("#password").val();
            if (jquery.trim(username) == '' || jquery.trim(password) == ''){
                return false;
            }
            else return true;
        });

jquery.trim()removes leading and trailing spaces, so just in case the user types a number of space characters it will be detected.

jquery.trim()删除前导和尾随空格,所以万一用户输入了一些空格字符,它将被检测到。

回答by Mayank

Instead of doing this, why not simply use the jQuery Validation Plugin - http://docs.jquery.com/Plugins/validation

而不是这样做,为什么不简单地使用 jQuery 验证插件 - http://docs.jquery.com/Plugins/validation

VALIDATE FORMS LIKE YOU'VE NEVER BEEN VALIDATING BEFORE! (According to the site)

以前所未有的方式验证表单!(据现场报道)

回答by Rob

In the html add this <input type="submit" value="SomeButton" onclick="return submitClicked();" />

在html中添加这个 <input type="submit" value="SomeButton" onclick="return submitClicked();" />

in the js do this

在 js 中这样做

function submitClicked() {
    if ($("#passwordInput").val() == '')
    {
        alert('missing password field');
        return false;
    }