java.lang.IllegalStateException: ArrayAdapter 要求资源 ID 为 TextView
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/23020408/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
java.lang.IllegalStateException: ArrayAdapter requires the resource ID to be a TextView
提问by Hamamelis
I tried this tutorial http://windrealm.org/tutorials/android/android-listview.php"A Simple Android ListView Example"
我试过这个教程http://windrealm.org/tutorials/android/android-listview.php“一个简单的 Android ListView 示例”
But in my test in Eclipse I've crash in android application.
但是在我在 Eclipse 中的测试中，我在 android 应用程序中崩溃了。
In LogCat I've this:
在 LogCat 我有这个：
04-11 20:17:24.170: E/AndroidRuntime(7062):
java.lang.IllegalStateException: ArrayAdapter requires the resource ID
to be a TextView
Why the crash ?
为什么会崩溃？
class java
类 java
private ListView mainListView;
private ArrayAdapter<String> listAdapter;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.mains);
mainListView = (ListView) findViewById(R.id.mainListView);
String[] xRemote = Remote.split(";");
ArrayList<String> planetList = new ArrayList<String>();
planetList.addAll(Arrays.asList(xRemote));
listAdapter = new ArrayAdapter<String>(this, R.layout.simplerow,
planetList);
listAdapter.addAll(xRemote);
mainListView.setAdapter(listAdapter);
mains.xml
电源文件
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent">
<ListView android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:id="@+id/mainListView">
</ListView
</LinearLayout>
simplerow.xml
simplerow.xml
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical" >
<TextView
android:id="@+id/rowTextView"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:padding="10dp"
android:textSize="16sp" >
</TextView>
</LinearLayout>
采纳答案by Emanuel Moecklin
Use
用
listAdapter = new ArrayAdapter<String>(this, R.layout.simplerow,
R.id.rowTextView, planetList);
The documentationsays:
该文件说：
By default this class expects that the provided resource id references a single TextView. If you want to use a more complex layout, use the constructors that also takes a field id. That field id should reference a TextView in the larger layout resource.
默认情况下，此类期望提供的资源 ID 引用单个 TextView。如果您想使用更复杂的布局，请使用也带有字段 id 的构造函数。该字段 id 应引用较大布局资源中的 TextView。
回答by Benoit
In simplerow.xml remove the LinearLayout and directly use TextView as the root
在 simplerow.xml 中去掉 LinearLayout 直接使用 TextView 作为根
