Java,将纬度/经度转换为 UTM

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时间:2020-08-11 10:53:54  来源:igfitidea点击:

Java, convert lat/lon to UTM

javageolocationlatitude-longitudegeographygeotools

提问by Steve Kuo

Does anyone know of a way, in Java, to convert an earth surface position from lat, lon to UTM (say in WGS84)? I'm currently looking at Geotools but unfortunately the solution is not obvious.

有谁知道在 Java 中将地球表面位置从纬度、经度转换为 UTM(例如在 WGS84 中)的方法?我目前正在研究 Geotools,但不幸的是,解决方案并不明显。

采纳答案by Steve Kuo

I was able to use Geotools 2.4 to get something that works, based on some example code.

根据一些示例代码,我能够使用 Geotools 2.4 来获得一些有用的东西。

double utmZoneCenterLongitude = ...  // Center lon of zone, example: zone 10 = -123
int zoneNumber = ...                 // zone number, example: 10
double latitude, longitude = ...     // lat, lon in degrees

MathTransformFactory mtFactory = ReferencingFactoryFinder.getMathTransformFactory(null);
ReferencingFactoryContainer factories = new ReferencingFactoryContainer(null);

GeographicCRS geoCRS = org.geotools.referencing.crs.DefaultGeographicCRS.WGS84;
CartesianCS cartCS = org.geotools.referencing.cs.DefaultCartesianCS.GENERIC_2D;

ParameterValueGroup parameters = mtFactory.getDefaultParameters("Transverse_Mercator");
parameters.parameter("central_meridian").setValue(utmZoneCenterLongitude);
parameters.parameter("latitude_of_origin").setValue(0.0);
parameters.parameter("scale_factor").setValue(0.9996);
parameters.parameter("false_easting").setValue(500000.0);
parameters.parameter("false_northing").setValue(0.0);

Map properties = Collections.singletonMap("name", "WGS 84 / UTM Zone " + zoneNumber);
ProjectedCRS projCRS = factories.createProjectedCRS(properties, geoCRS, null, parameters, cartCS);

MathTransform transform = CRS.findMathTransform(geoCRS, projCRS);

double[] dest = new double[2];
transform.transform(new double[] {longitude, latitude}, 0, dest, 0, 1);

int easting = (int)Math.round(dest[0]);
int northing = (int)Math.round(dest[1]);

回答by user2548538

No Library, No Nothing. Copy This!

没有图书馆,什么都没有。复制这个!

Using These Two Classes , You can Convert Degree(latitude/longitude) to UTM and Vice Versa!

使用这两个类,您可以将度数(纬度/经度)转换为 UTM,反之亦然!

private class Deg2UTM
{
    double Easting;
    double Northing;
    int Zone;
    char Letter;
    private  Deg2UTM(double Lat,double Lon)
    {
        Zone= (int) Math.floor(Lon/6+31);
        if (Lat<-72) 
            Letter='C';
        else if (Lat<-64) 
            Letter='D';
        else if (Lat<-56)
            Letter='E';
        else if (Lat<-48)
            Letter='F';
        else if (Lat<-40)
            Letter='G';
        else if (Lat<-32)
            Letter='H';
        else if (Lat<-24)
            Letter='J';
        else if (Lat<-16)
            Letter='K';
        else if (Lat<-8) 
            Letter='L';
        else if (Lat<0)
            Letter='M';
        else if (Lat<8)  
            Letter='N';
        else if (Lat<16) 
            Letter='P';
        else if (Lat<24) 
            Letter='Q';
        else if (Lat<32) 
            Letter='R';
        else if (Lat<40) 
            Letter='S';
        else if (Lat<48) 
            Letter='T';
        else if (Lat<56) 
            Letter='U';
        else if (Lat<64) 
            Letter='V';
        else if (Lat<72) 
            Letter='W';
        else
            Letter='X';
        Easting=0.5*Math.log((1+Math.cos(Lat*Math.PI/180)*Math.sin(Lon*Math.PI/180-(6*Zone-183)*Math.PI/180))/(1-Math.cos(Lat*Math.PI/180)*Math.sin(Lon*Math.PI/180-(6*Zone-183)*Math.PI/180)))*0.9996*6399593.62/Math.pow((1+Math.pow(0.0820944379, 2)*Math.pow(Math.cos(Lat*Math.PI/180), 2)), 0.5)*(1+ Math.pow(0.0820944379,2)/2*Math.pow((0.5*Math.log((1+Math.cos(Lat*Math.PI/180)*Math.sin(Lon*Math.PI/180-(6*Zone-183)*Math.PI/180))/(1-Math.cos(Lat*Math.PI/180)*Math.sin(Lon*Math.PI/180-(6*Zone-183)*Math.PI/180)))),2)*Math.pow(Math.cos(Lat*Math.PI/180),2)/3)+500000;
        Easting=Math.round(Easting*100)*0.01;
        Northing = (Math.atan(Math.tan(Lat*Math.PI/180)/Math.cos((Lon*Math.PI/180-(6*Zone -183)*Math.PI/180)))-Lat*Math.PI/180)*0.9996*6399593.625/Math.sqrt(1+0.006739496742*Math.pow(Math.cos(Lat*Math.PI/180),2))*(1+0.006739496742/2*Math.pow(0.5*Math.log((1+Math.cos(Lat*Math.PI/180)*Math.sin((Lon*Math.PI/180-(6*Zone -183)*Math.PI/180)))/(1-Math.cos(Lat*Math.PI/180)*Math.sin((Lon*Math.PI/180-(6*Zone -183)*Math.PI/180)))),2)*Math.pow(Math.cos(Lat*Math.PI/180),2))+0.9996*6399593.625*(Lat*Math.PI/180-0.005054622556*(Lat*Math.PI/180+Math.sin(2*Lat*Math.PI/180)/2)+4.258201531e-05*(3*(Lat*Math.PI/180+Math.sin(2*Lat*Math.PI/180)/2)+Math.sin(2*Lat*Math.PI/180)*Math.pow(Math.cos(Lat*Math.PI/180),2))/4-1.674057895e-07*(5*(3*(Lat*Math.PI/180+Math.sin(2*Lat*Math.PI/180)/2)+Math.sin(2*Lat*Math.PI/180)*Math.pow(Math.cos(Lat*Math.PI/180),2))/4+Math.sin(2*Lat*Math.PI/180)*Math.pow(Math.cos(Lat*Math.PI/180),2)*Math.pow(Math.cos(Lat*Math.PI/180),2))/3);
        if (Letter<'M')
            Northing = Northing + 10000000;
        Northing=Math.round(Northing*100)*0.01;
    }
}

private class UTM2Deg
{
    double latitude;
    double longitude;
    private  UTM2Deg(String UTM)
    {
        String[] parts=UTM.split(" ");
        int Zone=Integer.parseInt(parts[0]);
        char Letter=parts[1].toUpperCase(Locale.ENGLISH).charAt(0);
        double Easting=Double.parseDouble(parts[2]);
        double Northing=Double.parseDouble(parts[3]);           
        double Hem;
        if (Letter>'M')
            Hem='N';
        else
            Hem='S';            
        double north;
        if (Hem == 'S')
            north = Northing - 10000000;
        else
            north = Northing;
        latitude = (north/6366197.724/0.9996+(1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2)-0.006739496742*Math.sin(north/6366197.724/0.9996)*Math.cos(north/6366197.724/0.9996)*(Math.atan(Math.cos(Math.atan(( Math.exp((Easting - 500000) / (0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2))))*(1-0.006739496742*Math.pow((Easting - 500000) / (0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2)))),2)/2*Math.pow(Math.cos(north/6366197.724/0.9996),2)/3))-Math.exp(-(Easting-500000)/(0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2))))*( 1 -  0.006739496742*Math.pow((Easting - 500000) / (0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2)))),2)/2*Math.pow(Math.cos(north/6366197.724/0.9996),2)/3)))/2/Math.cos((north-0.9996*6399593.625*(north/6366197.724/0.9996-0.006739496742*3/4*(north/6366197.724/0.9996+Math.sin(2*north/6366197.724/0.9996)/2)+Math.pow(0.006739496742*3/4,2)*5/3*(3*(north/6366197.724/0.9996+Math.sin(2*north/6366197.724/0.9996 )/2)+Math.sin(2*north/6366197.724/0.9996)*Math.pow(Math.cos(north/6366197.724/0.9996),2))/4-Math.pow(0.006739496742*3/4,3)*35/27*(5*(3*(north/6366197.724/0.9996+Math.sin(2*north/6366197.724/0.9996)/2)+Math.sin(2*north/6366197.724/0.9996)*Math.pow(Math.cos(north/6366197.724/0.9996),2))/4+Math.sin(2*north/6366197.724/0.9996)*Math.pow(Math.cos(north/6366197.724/0.9996),2)*Math.pow(Math.cos(north/6366197.724/0.9996),2))/3))/(0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2))))*(1-0.006739496742*Math.pow((Easting-500000)/(0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2)))),2)/2*Math.pow(Math.cos(north/6366197.724/0.9996),2))+north/6366197.724/0.9996)))*Math.tan((north-0.9996*6399593.625*(north/6366197.724/0.9996 - 0.006739496742*3/4*(north/6366197.724/0.9996+Math.sin(2*north/6366197.724/0.9996)/2)+Math.pow(0.006739496742*3/4,2)*5/3*(3*(north/6366197.724/0.9996+Math.sin(2*north/6366197.724/0.9996)/2)+Math.sin(2*north/6366197.724/0.9996 )*Math.pow(Math.cos(north/6366197.724/0.9996),2))/4-Math.pow(0.006739496742*3/4,3)*35/27*(5*(3*(north/6366197.724/0.9996+Math.sin(2*north/6366197.724/0.9996)/2)+Math.sin(2*north/6366197.724/0.9996)*Math.pow(Math.cos(north/6366197.724/0.9996),2))/4+Math.sin(2*north/6366197.724/0.9996)*Math.pow(Math.cos(north/6366197.724/0.9996),2)*Math.pow(Math.cos(north/6366197.724/0.9996),2))/3))/(0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2))))*(1-0.006739496742*Math.pow((Easting-500000)/(0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2)))),2)/2*Math.pow(Math.cos(north/6366197.724/0.9996),2))+north/6366197.724/0.9996))-north/6366197.724/0.9996)*3/2)*(Math.atan(Math.cos(Math.atan((Math.exp((Easting-500000)/(0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2))))*(1-0.006739496742*Math.pow((Easting-500000)/(0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2)))),2)/2*Math.pow(Math.cos(north/6366197.724/0.9996),2)/3))-Math.exp(-(Easting-500000)/(0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2))))*(1-0.006739496742*Math.pow((Easting-500000)/(0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2)))),2)/2*Math.pow(Math.cos(north/6366197.724/0.9996),2)/3)))/2/Math.cos((north-0.9996*6399593.625*(north/6366197.724/0.9996-0.006739496742*3/4*(north/6366197.724/0.9996+Math.sin(2*north/6366197.724/0.9996)/2)+Math.pow(0.006739496742*3/4,2)*5/3*(3*(north/6366197.724/0.9996+Math.sin(2*north/6366197.724/0.9996)/2)+Math.sin(2*north/6366197.724/0.9996)*Math.pow(Math.cos(north/6366197.724/0.9996),2))/4-Math.pow(0.006739496742*3/4,3)*35/27*(5*(3*(north/6366197.724/0.9996+Math.sin(2*north/6366197.724/0.9996)/2)+Math.sin(2*north/6366197.724/0.9996)*Math.pow(Math.cos(north/6366197.724/0.9996),2))/4+Math.sin(2*north/6366197.724/0.9996)*Math.pow(Math.cos(north/6366197.724/0.9996),2)*Math.pow(Math.cos(north/6366197.724/0.9996),2))/3))/(0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2))))*(1-0.006739496742*Math.pow((Easting-500000)/(0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2)))),2)/2*Math.pow(Math.cos(north/6366197.724/0.9996),2))+north/6366197.724/0.9996)))*Math.tan((north-0.9996*6399593.625*(north/6366197.724/0.9996-0.006739496742*3/4*(north/6366197.724/0.9996+Math.sin(2*north/6366197.724/0.9996)/2)+Math.pow(0.006739496742*3/4,2)*5/3*(3*(north/6366197.724/0.9996+Math.sin(2*north/6366197.724/0.9996)/2)+Math.sin(2*north/6366197.724/0.9996)*Math.pow(Math.cos(north/6366197.724/0.9996),2))/4-Math.pow(0.006739496742*3/4,3)*35/27*(5*(3*(north/6366197.724/0.9996+Math.sin(2*north/6366197.724/0.9996)/2)+Math.sin(2*north/6366197.724/0.9996)*Math.pow(Math.cos(north/6366197.724/0.9996),2))/4+Math.sin(2*north/6366197.724/0.9996)*Math.pow(Math.cos(north/6366197.724/0.9996),2)*Math.pow(Math.cos(north/6366197.724/0.9996),2))/3))/(0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2))))*(1-0.006739496742*Math.pow((Easting-500000)/(0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2)))),2)/2*Math.pow(Math.cos(north/6366197.724/0.9996),2))+north/6366197.724/0.9996))-north/6366197.724/0.9996))*180/Math.PI;
        latitude=Math.round(latitude*10000000);
        latitude=latitude/10000000;
        longitude =Math.atan((Math.exp((Easting-500000)/(0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2))))*(1-0.006739496742*Math.pow((Easting-500000)/(0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2)))),2)/2*Math.pow(Math.cos(north/6366197.724/0.9996),2)/3))-Math.exp(-(Easting-500000)/(0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2))))*(1-0.006739496742*Math.pow((Easting-500000)/(0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2)))),2)/2*Math.pow(Math.cos(north/6366197.724/0.9996),2)/3)))/2/Math.cos((north-0.9996*6399593.625*( north/6366197.724/0.9996-0.006739496742*3/4*(north/6366197.724/0.9996+Math.sin(2*north/6366197.724/0.9996)/2)+Math.pow(0.006739496742*3/4,2)*5/3*(3*(north/6366197.724/0.9996+Math.sin(2*north/6366197.724/0.9996)/2)+Math.sin(2* north/6366197.724/0.9996)*Math.pow(Math.cos(north/6366197.724/0.9996),2))/4-Math.pow(0.006739496742*3/4,3)*35/27*(5*(3*(north/6366197.724/0.9996+Math.sin(2*north/6366197.724/0.9996)/2)+Math.sin(2*north/6366197.724/0.9996)*Math.pow(Math.cos(north/6366197.724/0.9996),2))/4+Math.sin(2*north/6366197.724/0.9996)*Math.pow(Math.cos(north/6366197.724/0.9996),2)*Math.pow(Math.cos(north/6366197.724/0.9996),2))/3)) / (0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2))))*(1-0.006739496742*Math.pow((Easting-500000)/(0.9996*6399593.625/Math.sqrt((1+0.006739496742*Math.pow(Math.cos(north/6366197.724/0.9996),2)))),2)/2*Math.pow(Math.cos(north/6366197.724/0.9996),2))+north/6366197.724/0.9996))*180/Math.PI+Zone*6-183;
        longitude=Math.round(longitude*10000000);
        longitude=longitude/10000000;       
    }   
}

回答by negora

For my projects I've using the library LatLongLib, from Ahmed Taha. I think that it's very easy to convert coordinates from the UTM system to the Latitude-Longitude system and vice-versa. You just need to play with the classes UTMUtils, UTMPoint and LatLonPoint.

对于我的项目,我使用了来自 Ahmed Taha的图书馆LatLongLib。我认为将坐标从 UTM 系统转换为经纬度系统非常容易,反之亦然。您只需要使用类 UTMUtils、UTMPoint 和 LatLonPoint。

Time ago I also considered choosing Jcoord. It was easy and straight to the point too. However, I needed to use the WGS84 ellipsoid and, at that time, only LatLongLib seemed to have that feature.

前段时间我也考虑过选择Jcoord。这也很简单,直截了当。但是,我需要使用 WGS84 椭球,当时似乎只有 LatLongLib 具有该功能。

回答by russellhoff

You can use this project https://github.com/Berico-Technologies/Geo-Coordinate-Conversion-Java/, adding it to your existing pom.xml using jitpack.

你可以使用这个项目https://github.com/Berico-Technologies/Geo-Coordinate-Conversion-Java/,使用 jitpack 将它添加到你现有的 pom.xml 中。

I've successfully been able to convert UTM coordinates (30N, this is, 30 zone and northern hemisphere) to Latitude and Longitude. See my example below:

我已经成功地将 UTM 坐标(30N,即 30 区和北半球)转换为纬度和经度。请参阅下面的示例:

public void setPunto(Point punto) {
    this.punto = punto;
    LatLon latlon = UTMCoord.locationFromUTMCoord(30, AVKey.NORTH, punto.getX(), punto.getY());
    this.latitud = latlon.getLatitude().degrees;
    this.longitud = latlon.getLongitude().degrees;
}

Note that Point class is of com.vividsolutions.jts.geom.Point class type.

请注意, Point 类是 com.vividsolutions.jts.geom.Point 类类型。

回答by Dominic

The transformation of a coordinate can actually be done in only a few lines of code:

坐标的变换实际上只需几行代码即可完成:

Coordinate coordinate = new Coordinate(x, y);
MathTransform transform = CRS.findMathTransform(CRS.decode("EPSG:4326"), CRS.decode("EPSG:3857"), false);
JTS.transform(coordinate, coordinate, transform); 

This will transform a longitude/latitude coordinate (EPSG:4326) into Web Mercator projection (EPSG:3857) coordinate.

这会将经度/纬度坐标 (EPSG:4326) 转换为 Web Mercator 投影 (EPSG:3857) 坐标。

You just need to depend on the following two GeoTools libraries in your build tool (e.g. maven):

您只需要在构建工具(例如 maven)中依赖以下两个 GeoTools 库:

<repositories>
    <repository>
        <id>osgeo</id>
        <name>Open Source Geospatial Foundation Repository</name>
        <url>http://download.osgeo.org/webdav/geotools/</url>
    </repository>
</repositories>

<dependencies>
    <dependency>
        <groupId>org.geotools</groupId>
        <artifactId>gt-api</artifactId>
        <version>${geotools.version}</version>
    </dependency>
    <dependency>
        <groupId>org.geotools</groupId>
        <artifactId>gt-epsg-hsql</artifactId>
        <version>${geotools.version}</version>
    </dependency>
</dependencies>

This answer builds on a question/replyon gis.stackexchange.com. Posted my reply because the current answers here seem to be quite verbose.

此答案基于gis.stackexchange.com上的问题/回复。发布我的回复是因为这里当前的答案似乎很冗长。