Javascript 如何使用 js eval 返回值?

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时间:2020-08-24 02:08:26  来源:igfitidea点击:

How can I use js eval to return a value?

javascript

提问by Radu094

I need to evaluate a custom function passed from the server as a string. It's all part of a complicated json I get, but anyway, I seem to be needing something along the lines:

我需要评估从服务器作为字符串传递的自定义函数。这都是我得到的复杂 json 的一部分,但无论如何,我似乎需要一些类似的东西:

var customJSfromServer = "return 2+2+2;"
var evalValue = eval(customJSfromServer);
alert(evalValue) ;// should be "6";

Obviously this is not working as I expected. Any way I can achieve this ?

显然,这不像我预期的那样工作。我有什么办法可以做到这一点?

回答by otakustay

The first method is to delete returnkeywords and the semicolon:

第一种方法是删除返回关键字和分号:

var expression = '2+2+2';
var result = eval('(' + expression + ')')
alert(result);

note the '('and ')'is a must.

注意'('')'是必须的。

or you can make it a function:

或者你可以把它变成一个函数:

var expression = 'return 2+2+2;'
var result = eval('(function() {' + expression + '}())');
alert(result);

even simpler, do not use eval:

更简单的是,不要使用 eval:

var expression = 'return 2+2+2;';
var result = new Function(expression)();
alert(result);

回答by Matt

If you can guarantee the returnstatement will always exist, you might find the following more appropriate:

如果您可以保证该return语句将始终存在,您可能会发现以下更合适:

var customJSfromServer = "return 2+2+2;"
var asFunc = new Function(customJSfromServer);
alert(asFunc()) ;// should be "6";

Of course, you could also do:

当然,你也可以这样做:

var customJSfromServer = "return 2+2+2;"
var evalValue = (new Function(customJSfromServer)());
alert(evalValue) ;// should be "6";

回答by chim

var customJSfromServer = "2+2+2;"
var evalValue = eval(customJSfromServer);
alert(evalValue) ;// should be "6";

回答by Alex Ciminian

This works:

这有效:

function answer() {
    return 42;
}

var a = eval('answer()');
console.log(a);

You need to wrap the return inside a function and it should pass the value on from the eval.

您需要将返回值包装在一个函数中,并且它应该从 eval 传递值。

回答by SergeS

There should not be return statement , as eval will read this as statment and will not return value.

不应该有 return 语句,因为 eval 会将其读为语句并且不会返回值。

var customJSfromServer = "2+2+2;"
var evalValue = eval( customJSfromServer );
alert(evalValue) ;// should be "6";

see http://www.w3schools.com/jsref/jsref_eval.asp

http://www.w3schools.com/jsref/jsref_eval.asp

回答by Matjaz Muhic

Modify server response to get "2+2+2" (remove "return") and try this:

修改服务器响应以获取“2+2+2”(删除“return”)并尝试以下操作:

var myvar = eval(response);
alert(myvar);

回答by leoncc

In 2019 using Template Literals:

2019 年使用模板文字:

var customJSfromServer = "2+2+2;"
var evalValue = eval(`${customJSfromServer}`);
alert(evalValue) ;// should be "6";