如何在 iOS 的 uiviewcontroller 中列出所有子视图？

How to list out all the subviews in a uiviewcontroller in iOS?

提问by user403015

I want to list out all the subviews in a UIViewController. I tried self.view.subviews, but not all of the subviews are listed out, for instance, the subviews in the UITableViewCellare not found. Any idea?

我想列出一个UIViewController. 我试过了self.view.subviews，但是不是所有的子视图都列出来了，比如UITableViewCell找不到子视图中的子视图。任何的想法？

回答by EmptyStack

You have to recursively iterate the sub views.

您必须递归迭代子视图。

- (void)listSubviewsOfView:(UIView *)view {

    // Get the subviews of the view
    NSArray *subviews = [view subviews];

    // Return if there are no subviews
    if ([subviews count] == 0) return; // COUNT CHECK LINE

    for (UIView *subview in subviews) {

        // Do what you want to do with the subview
        NSLog(@"%@", subview);

        // List the subviews of subview
        [self listSubviewsOfView:subview];
    }
}

---

---

As commented by @Greg Meletic, you can skip the COUNT CHECK LINE above.

正如@Greg Meletic 所评论的，您可以跳过上面的 COUNT CHECK LINE。

回答by natbro

The xcode/gdb built-in way to dump the view hierarchy is useful -- recursiveDescription, per http://developer.apple.com/library/ios/#technotes/tn2239/_index.html

转储视图层次结构的 xcode/gdb 内置方法很有用——recursiveDescription，根据http://developer.apple.com/library/ios/#technotes/tn2239/_index.html

It outputs a more complete view hierarchy which you might find useful:

它输出一个更完整的视图层次结构，您可能会发现它很有用：

> po [_myToolbar recursiveDescription]

<UIToolbarButton: 0xd866040; frame = (152 0; 15 44); opaque = NO; layer = <CALayer: 0xd864230>>
   | <UISwappableImageView: 0xd8660f0; frame = (0 0; 0 0); opaque = NO; userInteractionEnabled = NO; layer = <CALayer: 0xd86a160>>

回答by Alex

Elegant recursive solution in Swift:

Swift 中优雅的递归解决方案：

extension UIView {

    func subviewsRecursive() -> [UIView] {
        return subviews + subviews.flatMap { 
let allSubviews = self.view.subviewsRecursive()
.subviewsRecursive() }
    }

}

You can call subviewsRecursive() on any UIView:

您可以在任何 UIView 上调用 subviewsRecursive()：

-(void) printAllChildrenOfView:(UIView*) node depth:(int) d
{
    //Tabs are just for formatting
    NSString *tabs = @"";
    for (int i = 0; i < d; i++)
    {
        tabs = [tabs stringByAppendingFormat:@"\t"];
    }

    NSLog(@"%@%@", tabs, node);

    d++; //Increment the depth
    for (UIView *child in node.subviews)
    {
        [self printAllChildrenOfView:child depth:d];
    }

}

回答by James Webster

You need to print recursively, this method also tabs based on the depth of the view

您需要递归打印，此方法还基于视图的深度进行制表

 func listSubviewsOfView(view:UIView){

    // Get the subviews of the view
    var subviews = view.subviews

    // Return if there are no subviews
    if subviews.count == 0 {
        return
    }

    for subview : AnyObject in subviews{

        // Do what you want to do with the subview
        println(subview)

        // List the subviews of subview
        listSubviewsOfView(subview as UIView)
    }
}

回答by Arkader

Here is the swift version

这是快速版本

@implementation UIView (childViews)

- (NSArray*) allSubviews {
    __block NSArray* allSubviews = [NSArray arrayWithObject:self];

    [self.subviews enumerateObjectsUsingBlock:^( UIView* view, NSUInteger idx, BOOL*stop) {
        allSubviews = [allSubviews arrayByAddingObjectsFromArray:[view allSubviews]];
                   }];
        return allSubviews;
    }

@end

回答by Gordon Dove

I'm a bit late to the party, but a bit more general solution:

我参加聚会有点晚了，但更通用的解决方案是：

extension UIView {
  var allSubviews: [UIView] {
    return self.subviews.reduce([UIView]()) { 
NSLog(@"%@", [self.view subviews]);
 + [] + .allSubviews }
  }
}

回答by Federico Zanetello

If all you want is an array of UIViews, this is a one liner solution (Swift 4+):

如果你想要的只是一个UIViews数组，这是一个单行解决方案（Swift 4+）：

extension UIView {
    private func subviews(parentView: UIView, level: Int = 0, printSubviews: Bool = false) -> [UIView] {
        var result = [UIView]()
        if level == 0 && printSubviews {
            result.append(parentView)
            print("\(parentView.viewInfo)")
        }

        for subview in parentView.subviews {
            if printSubviews { print("\(String(repeating: "-", count: level))\(subview.viewInfo)") }
            result.append(subview)
            if subview.subviews.isEmpty { continue }
            result += subviews(parentView: subview, level: level+1, printSubviews: printSubviews)
        }
        return result
    }
    private var viewInfo: String { return "\(classForCoder), frame: \(frame))" }
    var allSubviews: [UIView] { return subviews(parentView: self) }
    func printSubviews() { _ = subviews(parentView: self, printSubviews: true) }
}

回答by Graphite

I use this way:

我用这种方式：

 view.printSubviews()
 print("\(view.allSubviews.count)")

in the UIViewController.

在 UIViewController 中。

回答by Vasily Bodnarchuk

Details

细节

• Xcode 9.0.1, Swift 4
• Xcode 10.2 (10E125), Swift 5

• Xcode 9.0.1，斯威夫特 4
• Xcode 10.2 (10E125)，Swift 5

Solution

解决方案

@implementation UIView (Recurrence)

- (NSArray<UIView *> *)recurrenceAllSubviews
{
    NSMutableArray <UIView *> *all = @[].mutableCopy;
    void (^getSubViewsBlock)(UIView *current) = ^(UIView *current){
        [all addObject:current];
        for (UIView *sub in current.subviews) {
            [all addObjectsFromArray:[sub recurrenceAllSubviews]];
        }
    };
    getSubViewsBlock(self);
    return [NSArray arrayWithArray:all];
}
@end

Usage

用法

NSArray *views = [viewController.view recurrenceAllSubviews];

Result

结果

回答by Zhiping Yang

In my way, UIView's category or extension is much better than others and recursive is the key point to get all subviews

以我的方式，UIView的category或extension比其他的好很多，递归是获取所有子视图的关键

learn more:

了解更多：

https://github.com/ZhipingYang/XYDebugView

https://github.com/ZhipingYang/XYDebugView

Objective-C

目标-C

extension UIView {
    func recurrenceAllSubviews() -> [UIView] {
        var all = [UIView]()
        func getSubview(view: UIView) {
            all.append(view)
            guard view.subviews.count>0 else { return }
            view.subviews.forEach{ getSubview(view: 
let views = viewController.view.recurrenceAllSubviews()
) }
        }
        getSubview(view: self)
        return all
    }
}

example

例子

let viewSequence = sequence(state: [viewController.view]) { (state: inout [UIView] ) -> [UIView]? in
    guard state.count > 0 else { return nil }
    defer {
        state = state.map{ ##代码##.subviews }.flatMap{ ##代码## }
    }
    return state
}
let views = viewSequence.flatMap{ ##代码## }

Swift 3.1

斯威夫特 3.1

##代码##

example

例子

##代码##

directly, use sequencefunction to get all subviews

直接使用sequence函数获取所有子视图

##代码##