bash 如何使用shell脚本计算每行中的选项卡数量？
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How to count number of tabs in each line using shell script?
提问by bcd
I need to write a script to count the number of tabs in each line of a file and print the output to a text file (e.g., output.txt).
我需要编写一个脚本来计算文件每一行中的选项卡数量并将输出打印到文本文件（例如，output.txt）。
How do I do this?
我该怎么做呢？
回答by bcd
awk '{print gsub(/\t/,"")}' inputfile > output.txt
回答by chepner
If you treat \tas the field delimiter, there will be one fewer \tthan fields on each line:
如果您将其\t视为字段分隔符，则\t每行将少于一个字段：
awk -F'\t' '{ print NF-1 }' input.txt > output.txt
回答by Rostyslav
This will give the total number of tabs in file:
这将给出文件中的标签总数：
od -c infile | grep -o "\t" | wc -l > output.txt
This will give you number of tabs line by line:
这将为您逐行提供标签数量：
awk '{print gsub(/\t/,"")}' infile > output.txt
