php PHP通过将天数添加到可变日期来计算未来日期
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PHP Calculating future date by adding days to a variable date
提问by OneNerd
I was looking at this post, and it is close to what I need: PHP - How to count 60 days from the add date
我正在看这篇文章，它接近我需要的内容： PHP - 如何从添加日期算起 60 天
However, in that post, the calculation is performed by adding 60 days to the current date. What I need to do is calculate the date based on a variable date (and not the current date).
但是，在该帖子中，计算是通过将 60 天添加到当前日期来执行的。我需要做的是根据可变日期（而不是当前日期）计算日期。
Something like this:
像这样的东西：
$my_date = $some_row_from_a_database;
$date_plus_10_days = ???;
Anyone know how to do that?
有谁知道怎么做？
Thanks
谢谢
回答by Michael Mrozek
You can put something before the "+10 days" part:
你可以在“+10天”部分之前放一些东西：
strtotime("2010-01-01 +10 days");
回答by jpabluz
Use date_add
使用 date_add
http://www.php.net/manual/en/datetime.add.php
http://www.php.net/manual/en/datetime.add.php
$my_date = new DateTime($some_row_from_a_database);
$date_plus_10_days = date_add($my_date, new DateInterval('P10D'));
回答by Faisal
You will have to look into strtotime(). I'd imagine your final code would look something like this:
您将不得不研究strtotime()。我想你的最终代码会是这样的：
$dateVariable = strtotime('2017-01-29');//your date variable goes here
$date_plus_60_days = date('Y-m-d', strtotime('+ 60 days', $dateVariable));
echo $date_plus_60_days;
If you are using PHP >= 5.2 I strongly suggest you use the new DateTime object. For example like below:
如果您使用的是 PHP >= 5.2，我强烈建议您使用新的 DateTime 对象。例如像下面这样：
$date_plus_60_days = new DateTime("2006-12-12");
$date_plus_60_days->modify("+60 days");
echo $date_plus_60_days->format("Y-m-d");
回答by Santin
I see you are retriving data from a database. If you are using mysql you can do it on the select:
我看到您正在从数据库中检索数据。如果您使用的是 mysql，则可以在选择上执行此操作：
Example: you need the last date of the table and this date-7 days
示例：您需要表的最后日期和此日期-7 天
select max(datefield) as ultimaf, DATE_SUB(max(datefield),INTERVAL 7 DAY) as last7
from table
It′s easy use curdate() if you want todays date.
如果你想要今天的日期，使用 curdate() 很容易。
If you need a dynamic between that selects the count of last 7 days:
如果您需要动态选择过去 7 天的计数：
select count(*) from table
where DATE_SUB(CURDATE(),INTERVAL 7 DAY)<=datefield"
回答by R T
date('Y-m-d H:i:s', strtotime("2014-11-24 06:33:39" +35 days"))
this will get the calculated date in defined format.
这将获得定义格式的计算日期。
回答by sandeep kasar
Suppose today's date is
假设今天的日期是
date_default_timezone_set('Asia/Calcutta');
$today=date("Y-m-d");
And i can add 10 days in current date as follows :
我可以在当前日期添加 10 天，如下所示：
$date_afte_10_days = date('Y-m-d', strtotime("$today +10 days"));
