如何在 selenium webdriver for java 中按索引查找元素
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How to find an Element by index in selenium webdriver for java
提问by Tim Boland
Im trying to automate the Google Images page:
我正在尝试自动化 Google 图片页面：
All the images have the same class but no id and the results are constantly changing. So I would like to be able to click on the images based on their index.
所有图像都具有相同的类但没有 id，并且结果不断变化。所以我希望能够根据他们的索引点击图像。
I know how to do it in C#...but I cant figure out how to specify in the index in Java. When I try to select an index beyond 0, I get and IndexOutOfBounds error, but i cant figure out why
我知道如何在 C# 中做到这一点......但我无法弄清楚如何在 Java 中的索引中指定。当我尝试选择大于 0 的索引时，出现 IndexOutOfBounds 错误，但我不知道为什么
WebElement image = chromeDriver.findElement(By.className("rg_di"));
WebElement imageLink = image.findElements(By.tagName("a")).get(1);
imageLink.click();
Here is the entire code im using...any help would be appreciated:
这是我使用的整个代码......任何帮助将不胜感激：
System.setProperty("webdriver.chrome.driver", "/Users/user/chromedriver");
WebDriver chromeDriver = new ChromeDriver();
chromeDriver.get("http://www.google.com");
WebElement searchBox = chromeDriver.findElement(By.id("gbqfq"));
searchBox.sendKeys("pluralsight");
searchBox.sendKeys(Keys.RETURN);
chromeDriver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);
WebElement imagesLink = chromeDriver.findElement(By.linkText("Images"));
imagesLink.click();
WebElement image = chromeDriver.findElement(By.className("rg_di"));
WebElement imageLink = image.findElements(By.tagName("a")).get(1);
imageLink.click();
Any help would be greatly appreciated
任何帮助将不胜感激
采纳答案by cbarreras
In your code:
在您的代码中：
WebElement image = chromeDriver.findElement(By.className("rg_di"));
will return the first element found on the page with a class of "rg_di".
将返回在页面上找到的第一个具有“rg_di”类的元素。
That element has only one <a href=... /a>tag in it.
该元素中只有一个<a href=... /a>标签。
You are getting an IndexOutOfBounds exception because you are asking for the secondone (zero based indexing). If you change your final WebElement to:
您收到 IndexOutOfBounds 异常，因为您要求第二个（基于零的索引）。如果您将最终的 WebElement 更改为：
WebElement imageLink = image.findElements(By.tagName("a")).get(0);
The code should work for you with that small change.
代码应该可以通过这个小的更改为您工作。
This is my quick version (note the lack of storing elements I only need to do one thing with as WebElements):
这是我的快速版本（注意缺少存储元素，我只需要用 WebElements 做一件事）：
public static void main(String[] args) {
// I don't have Chrome installed >.<
WebDriver driver = new FirefoxDriver();
driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);
driver.get("http://www.google.com");
WebElement searchBox = driver.findElement(By.id("gbqfq"));
searchBox.sendKeys("pluralsight");
searchBox.sendKeys(Keys.RETURN);
driver.findElement(By.linkText("Images")).click();
WebElement image = driver.findElement(By.className("rg_di"));
image.findElements(By.tagName("a")).get(0).click();
// super-shortened version:
// driver.findElement(By.className("rg_di")).findElements(By.tagName("a")).get(0).click();
}
回答by bcar
I'd do:
我会做：
List<WebElement> we = chromeDriver.findElements(By.cssSelector(".your-class a"));
we.get(1) //should get first element in array
回答by Pardhiva E
This code worked very well when we have similar object properties for same web buttons, then using
当我们对相同的 Web 按钮具有相似的对象属性时，此代码运行得非常好，然后使用
List<WebElement> we = webdriver.findElements(By.cssSelector(""));
and then getting
然后得到
we.get(1).click();
Thank you so much for posting this answer.
非常感谢您发布此答案。
回答by Beytullah uzun
Another solution may be like this: If the class name and the index of the web element are known, then following code works:
另一种解决方案可能是这样的：如果已知 web 元素的类名和索引，则以下代码有效：
driver.findElement(By.xpath("(//*[@class='android.widget.ImageView'])[18]")).click();
