C语言 C - scanf,printf 名称和年龄程序
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C - scanf,printf name and age program
提问by Spiros Kmaris
#include <stdio.h>
int main ()
{
char yourname;
int yourage;
printf("Whats your name?\t");
scanf("%c",&yourname);
printf("How old are you?\t");
scanf("%d",&yourage);
printf("You are %d years old and your name is %c\n\n\n",yourage,yourname);
system("pause");
return(0);
}
I want this program to ask for the username and age, and then print them..
我想让这个程序询问用户名和年龄，然后打印出来。
采纳答案by crashxxl
when you use scanf, %cis intended to get a single character. If you want to get a string, you need to use %s.
当您使用scanf,时，%c旨在获取单个字符。如果要获取字符串，则需要使用%s.
Also, in C langage, string are just char arrays. So you need to declare a char array.
此外，在 C 语言中，字符串只是字符数组。所以你需要声明一个char数组。
#include <stdio.h>
int main ()
{
char yourname[100];
int yourage;
printf("Whats your name?\t");
scanf("%s",yourname); //i let you read the doc to avoid overflow :)
printf("How old are you?\t");
scanf("%d",&yourage);
printf("You are %d years old and your name is %s \n\n\n",yourage,yourname);
system("pause");
return(0);
}
回答by Rizier123
This should work for you:
这应该适合你：
#include <stdio.h>
int main () {
char yourname[20];
int yourage;
printf("Whats your name?\t");
scanf("%18[^\n]s", yourname);
yourname[19] = '##代码##';
fflush(stdin);
printf("How old are you?\t");
scanf(" %d",&yourage);
printf("You are %d years old and your name is %s\n\n\n", yourage, yourname);
system("pause");
return(0);
}
