Javascript 禁用警报（）；
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Disable alert();
提问by specked
Code that is generated on my page that I cannot control contains an alert. Is there a jQuery or other way to disable alert() from working?
在我无法控制的页面上生成的代码包含警报。是否有 jQuery 或其他方法来禁用 alert() 工作？
The javascript that is being generated that I want to disable/modify is:
我要禁用/修改的正在生成的 javascript 是：
function fndropdownurl(val)
1317 { var target_url
1318 target_url = document.getElementById(val).value;
1319 if (target_url == 0)
1320 {
1321 alert("Please Select from DropDown")
1322 }
1323 else
1324 {
1325 window.open(target_url);
1326 return;
1327 }
1328 }
I want to disable the alert on line 1321
我想禁用第 1321 行的警报
Thanks
谢谢
回答by Andrew Moore
Simply overwrite alertwith your own, empty, function.
只需alert用您自己的空函数覆盖即可。
window.alert = function() {};
// or simply
alert = function() {};
回答by joar
This works in Chrome and other browsers with the console.logfunction.
这适用于 Chrome 和其他具有该console.log功能的浏览器。
window.alert = function ( text ) { console.log( 'tried to alert: ' + text ); return true; };
alert( new Date() );
// tried to alert: Wed Dec 08 2010 14:58:28 GMT+0100 (W. Europe Standard Time)
回答by Vlad.P
You can try and make a new function function alert() { }, this is not going to do anything since is empty and will overwrite the existing one.
您可以尝试创建一个新函数function alert() { }，这不会做任何事情，因为它是空的，并且会覆盖现有的函数。
回答by James Wiseman
Try this:
尝试这个：
alert("test");
alert = function(){};
alert("test");
The second line assigns a new blank function to alert, while not breaking the fact that it is a function. See: http://jsfiddle.net/9MHzL/
第二行为 alert 分配了一个新的空白函数，同时不破坏它是一个函数的事实。见：http: //jsfiddle.net/9MHzL/
