C# 如何在asp.net的gridview中创建链接

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时间:2020-08-10 15:55:03  来源:igfitidea点击:

how to create a link in gridview in asp.net

c#asp.netgridviewlinkbutton

提问by Arif YILMAZ

I am trying to create a webpage that has a gridview. this gridview is supposed to have a link like below

我正在尝试创建一个具有 gridview 的网页。这个gridview应该有一个像下面这样的链接

http://localhost/Test.aspx?code=123

when the user clicks one of the rows' link in gridview, it will open a blank page and display some result.

当用户单击 gridview 中的行链接之一时,它将打开一个空白页面并显示一些结果。

here is how I bind data to the gridview but I dont know how to set the link

这是我如何将数据绑定到 gridview 但我不知道如何设置链接

protected void Page_Load(object sender, EventArgs e)
{
    string firma_no = logoFrmNr.ToString().PadLeft(3, '0');
    string active_period = logoFrmPeriod.PadLeft(2, '0');

    SqlConnection conn = new SqlConnection(conStr);
    string selectSql = @"SELECT 
                                LOGICALREF,
                                CODE , 
                                DEFINITION_ ,
                                FROM 
                                LG_CLFLINE";

    SqlCommand cmd = new SqlCommand(selectSql, conn);
    DataTable dt = new DataTable();
    SqlDataAdapter da = new SqlDataAdapter(cmd);
    da.Fill(dt);
    GridView1.DataSource = dt;
    GridView1.DataBind();

    conn.Close();
}

here is the markup

这是标记

<asp:GridView ID="GridView1" runat="server" EnableModelValidation="True">
</asp:GridView>

How can I make a link out of CODE column?

如何从 CODE 列中创建链接?

采纳答案by Smeegs

There's a trick to this. The Hyperlinkcolumn won't work, because you can't format the link. You want to use a boundfield and format the text. Like so

这有一个技巧。Hyperlinkcolumn 将不起作用,因为您无法格式化链接。您想使用边界字段并格式化文本。像这样

<asp:GridView ID="GridView1" runat="server" EnableModelValidation="True">
    <Columns>
        <asp:BoundField DataField="Code" HtmlEncode="False" DataFormatString="<a target='_blank' href='Test.aspx?code={0}'>Link Text Goes here</a>" />
    </Columns>
</asp:GridView>

Alternately, you can use a templatefield if you need to designate edit and insert templates.

或者,如果您需要指定编辑和插入模板,您可以使用模板字段。

回答by Tim

You should be able to use a HyperLinkColumn in your markup.

您应该能够在标记中使用 HyperLinkColumn。

HyperlinkColumn Documentation

超链接列文档

回答by Karl Anderson

Add this to your Columnsdefinition in the markup for your grid view:

将此添加到您Columns的网格视图标记中的定义中:

<asp:TemplateField HeaderText="Hyperlink">
    <ItemTemplate>
        <asp:HyperLink ID="HyperLink1" runat="server" 
            NavigateUrl='<%# Eval("CODE", @"http://localhost/Test.aspx?code={0}") %>' 
            Text='link to code'>
        </asp:HyperLink>
    </ItemTemplate>
</asp:TemplateField>

回答by Hyman.the.ripper

to me it would be something like

对我来说就像

<asp:DataGrid id="MyDataGrid" 
           GridLines="Both"
           AutoGenerateColumns="false"
           runat="server">

         <HeaderStyle BackColor="#aaaadd"/>

         <Columns>

            <asp:HyperLinkColumn
                 HeaderText="Select an Item"
                 DataNavigateUrlField="code"
                 DataNavigateUrlFormatString="http://localhost/Test.aspx?code={0}"
                 Target="_blank"/>

         </Columns>

      </asp:DataGrid>