C语言 如何在GDB中查看像数组一样的指针？
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How to view a pointer like an array in GDB?
提问by CDT
Suppose defined: int a[100]Type print athen gdb will automatically display it as an array:1, 2, 3, 4.... However, if ais passed to a function as a parameter, then gdb will treat it as a normal int pointer, type print awill display:(int *)0x7fffffffdaa0. What should I do if I want to view aas an array?
假设定义：int a[100]键入print a然后 gdb 将自动将其显示为数组：1, 2, 3, 4...。但是，如果a作为参数传递给函数，则 gdb 会将其视为普通的 int 指针，typeprint a将显示：(int *)0x7fffffffdaa0。如果我想以a数组形式查看该怎么办？
回答by R.. GitHub STOP HELPING ICE
*(T (*)[N])pwhere T is the type, N is the number of elements and p is the pointer.
*(T (*)[N])p其中 T 是类型，N 是元素数，p 是指针。
回答by aschepler
Use the xcommand.
使用x命令。
(gdb) x/100w a
