eclipse 连接到 Tomcat 上的套接字？
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Connecting to socket on Tomcat?
提问by Sbram
I'm trying to connect from a standalone applet to a servlet running on tomcat:
我正在尝试从独立小程序连接到在 tomcat 上运行的 servlet：
Servlet
小服务程序
public void init(ServletConfig config) throws ServletException {
super.init(config);
// Start a daemon thread
try {
daemonThread = new Daemon(this);
daemonThread.start();
}
catch (Exception e) {
}
}
protected int getSocketPort() {
return 8080;
}
public void handleClient(Socket client){
new ScribbleThread(this, client).start();
}
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
PrintWriter out = response.getWriter();
StringBuffer sb = new StringBuffer();
sb.append("<html><body bgcolor=pink text=red>");
sb.append("<h1 align=center>RUNNING</h1><hr>");
sb.append("</body></html>");
out.println(sb);
out.close();
}
}
Servlet's init()creates this:
Servlet 的init()创建是这样的：
class Daemon extends Thread {
private ServerSocket serverSocket;
private SocketServlet servlet;
public Daemon(SocketServlet servlet) {
this.servlet = servlet;
}
public void run() {
try {
// Create a server socket to accept connections
serverSocket = new ServerSocket(servlet.getSocketPort());
}
catch (Exception e) {
return;
}
try {
while (true) {
try {
servlet.handleClient(serverSocket.accept());
}
catch (IOException ioe) {
}
}
}
I have this deployed by eclipse to TomCat. My question is what address does my applet need to make the socket to? When i visit http://localhost:8080/scrabServ/connectI see the 'RUNNING' message from the doGet()so is that where it needs to point?
我已经通过 Eclipse 将它部署到 TomCat。我的问题是我的小程序需要将套接字连接到哪个地址？当i visit http://localhost:8080/scrabServ/connect我看到来自“正在运行”的消息时doGet()，它需要指向哪里？
Applet:
小程序：
public static String testConnection(){
InputStream in = null;
try {
// Make socket connection to servlet
String servlet = new String("localhost/scrabServ/connect");
Socket socket = new Socket(servlet, 8080);
this gives me:
这给了我：
Exception in testConnection()java.net.UnknownHostException: localhost/scrabServ/connect
at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:195)
at java.net.SocksSocketImpl.connect(SocksSocketImpl.java:432)
at java.net.Socket.connect(Socket.java:529)
at java.net.Socket.connect(Socket.java:478)
at java.net.Socket.<init>(Socket.java:375)
at java.net.Socket.<init>(Socket.java:189)
at scribble.Scribble.testConnection(Scribble.java:41)
at scribble.Scribble.main(Scribble.java:28)
and points to the new Socket(servlet, 8080)line.
并指向new Socket(servlet, 8080)线。
采纳答案by Marcelo
You would have only to open a socket to "localhost", 8080and then issue a GET scrabServ/connectcommand. You can't open a socket to a specific URL.
您只需打开一个套接字"localhost", 8080，然后发出一个GET scrabServ/connect命令。您无法打开特定 URL 的套接字。
To communicate with a servlet you do it via request parameters, basically issuing a GET command such as: http://www.jmarshall.com/easy/http/http_footnotes.html#getsubmit
要与 servlet 通信，您可以通过请求参数进行通信，基本上是发出 GET 命令，例如：http: //www.jmarshall.com/easy/http/http_footnotes.html#getsubmit
Maybe you should use URLConnectioninstead. If you detail what exactly you want to do, maybe I can have a better idea of how to help you, maybe a HTTP server is not even needed for what you want to do.
也许您应该改用URLConnection。如果您详细说明您想要做什么，也许我可以更好地了解如何帮助您，也许您想要做的事情甚至不需要 HTTP 服务器。
