Java 从 XML 中的子节点获取父信息
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Getting parent information from child node in XML
提问by Roboute Guilliman
I currently have some xml along the lines of:
我目前有一些 xml:
<Schools>
<School SchoolName="name1" ... >
<Students>
<Student studentName="student1" .../>
<Student studentName="student2" .../>
</Stuidents>
</School>
<School SchoolName="name2" ...>
<Students>
<Student studentName="student3" ... />
<Student studentName="student3" ... />
</Students>
</School>
</Schools>
If I make a node list of "School" and "Student" using a DOM parser, within the Student node list how am I able to get SchoolName from the student so that I am able to save in a Database/Student Class : StudentName, Student Details, SchoolName.
如果我使用 DOM 解析器制作“学校”和“学生”的节点列表,在学生节点列表中,我如何从学生那里获取 SchoolName 以便我能够保存在数据库/学生类中:StudentName,学生详细信息,学校名称。
NodeList schoolNodeList = docEle.getElementsByTagName("School");
NodeList studentNodeList = docEle.getElementsByTagName("Student");
parseStudentNodeList(studentNodeList);
private void parseStudentNodeList(NodeList studentsNodeList)
{
Student student = new Student();
for (int i = 0; i < studentNodeList.getLength(); i++)
{
Element el (Element) studentNodeList.item(i);
student.setName(el.getAttribute("studentName"));
student.setSchool( /* Help needed here */ );
}
}
Preferably by not adding a "SchoolName" variable into the Student section.
最好不要在学生部分添加“学校名称”变量。
采纳答案by Developer Marius ?il?nas
Each node has method getParentNode(), you could get node's parent node.
每个节点都有方法getParentNode(),您可以获取节点的父节点。