java 如何在 Mule Dataweave 转换中使用正则表达式替换特殊字符？
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How to replace special character using regex in Mule Dataweave transformation?
提问by Aditya
Suppose I have an XML file of details of employee such as id, name and address and now I want to convert it into JSON file and before the conversation I want to replace specified special character (- , /) with blank space in address field of json document
假设我有一个包含员工详细信息（例如 ID、姓名和地址）的 XML 文件，现在我想将其转换为 JSON 文件，并且在对话之前我想用地址字段中的空格替换指定的特殊字符 (-, /) json文件
below are my Dataweave transformation code
下面是我的Dataweave 转换代码
%dw 1.0
%output application/json
---
payload map ((payload01 , indexOfPayload01) -> {
Id: payload01 .d as :string,
Name: payload01.Name as :string,
Address: payload01.Address replace /(?)/ with " "
})
So what should I write within replace /()/ function to replace specials character ,-and /with blank space?
那么我应该在 replace /()/ 函数中写什么来用空格替换特殊字符、-和/？
回答by user3928757
Please try the following code
请尝试以下代码
Address: payload01.Address replace /([\-\,\/])/ with " "
