javascript 根据嵌套值按字典顺序对对象数组进行排序
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Sort a array of objects lexicographically based on a nested value
提问by Sachin
Using Javascript, I would like to know how to sort lexicographically a array of objects based on a string value in each object.
使用Javascript，我想知道如何根据每个对象中的字符串值按字典顺序对对象数组进行排序。
Consider:
考虑：
[
{
"name" : "bob",
"count" : true
"birthday" : 1972
},
{
"name" : "jill",
"count" : false
"birthday" : 1922
},
{
"name" : "Gerald",
"count" : true
"birthday" : 1920
}
]
How can I sort the array alphabetically by name? The name values are usernames, so I would like to maintain the letter casing.
如何按名称的字母顺序对数组进行排序？名称值是用户名，所以我想保持字母大小写。
回答by davin
var obj = [...];
obj.sort(function(a,b){return a.name.localeCompare(b.name); });
Be aware that this will not take capitalisation into account (so it will order all names beginning with capitals before all those beginning with smalls, i.e. "Z" < "a"), so you might find it relevant to add a toUpperCase()in there.
请注意，这不会考虑大写（因此它会将所有以大写开头的名称排序在所有以小写开头的名称之前，即"Z" < "a"），因此您可能会发现toUpperCase()在其中添加 a是相关的。
You can make it more generic as well:
你也可以让它更通用：
function sortFactory(prop) {
return function(a,b){ return a[prop].localeCompare(b[prop]); };
}
obj.sort(sortFactory('name')); // sort by name property
obj.sort(sortFactory('surname')); // sort by surname property
And even more generic if you pass the comparator to the factory...
如果您将比较器传递给工厂，则更通用......
回答by jabclab
This will do it:
这将做到：
arr.sort(function(a, b) {
return a.name.localeCompare(b.name);
});
回答by Cesar Canassa
Using comparison
使用比较
arr.sort(function (a, b) {return a.name.toLowerCase() > b.name.toLowerCase()})
https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/String#Comparing_strings
https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/String#Comparing_strings
