将多维数组中的所有整数相加 javascript
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Sum all integers in a multidimensional array javascript
提问by VoA
Let's say I have this:
假设我有这个:
function arrSum(){
*code here*
}
How do I write the arrSum function such that it can sum all the integers within a multidimensional array (of variable depth).
我如何编写 arrSum 函数,以便它可以对多维数组(可变深度)中的所有整数求和。
I.e.
IE
arrSum([2, 5, [4, 6], 5]) === 22;
I know there must be an answer to this somewhere but I really can't find it. If this is a duplicate please let me know.
我知道某个地方一定有这个问题的答案,但我真的找不到。如果这是重复的,请告诉我。
回答by Pranav C Balan
Simply you can write a function like this with recursion
只需您可以使用递归编写这样的函数
function arrSum(arr) {
var sum = 0;
// iterate array using forEach, better to use for loop since it have higher performance
arr.forEach(function(v) {
// checking array element is an array
if (typeof v == 'object')
// if array then getting sum it's element (recursion)
sum += arrSum(v);
else
// else adding the value with sum
sum += v
})
// returning the result
return sum;
}
console.log(arrSum([2, 5, [4, 6], 5]) === 22);
Using for
loop
使用for
循环
function arrSum(arr) {
var sum = 0;
for (var i = 0; i < arr.length; i++) {
if (typeof arr[i] == 'object')
sum += arrSum(arr[i]);
else
sum += arr[i];
}
return sum;
}
console.log(arrSum([2, 5, [4, 6], 5]) === 22);
回答by ryanpcmcquen
回答by Anshuman
Check this:
检查这个:
function arrSum(objArr){
var total = 0;
for(var outerLoop=0; outerLoop < objArr.length; outerLoop++){
if(objArr[outerLoop].constructor === Array){
for(var innerLoop=0; innerLoop < objArr[outerLoop].length; innerLoop++){
total += objArr[outerLoop][innerLoop];
}
} else {
total += objArr[outerLoop];
}
}
return total;
}
alert (arrSum([2, 5, [4, 6], 5]));
回答by DevDeb
function arrSum(arr) {
var totalSum = null;
var numString = arr.toString();
var numberArray = numString.split(",");
numberArray.forEach(function(ele){
totalSum = totalSum + parseInt(ele);
});
return totalSum;
}
console.log(arrSum([2, 5, [4, 6], 5]);
回答by Safia Nuzhath
If we have a multi-dimensional array with strings and integers and we have to get the sum of the numbers, then following @Pranav C Balan's solution we could add a check in the else loop to check only for digits as below -
如果我们有一个包含字符串和整数的多维数组并且我们必须得到数字的总和,那么按照@Pranav C Balan 的解决方案,我们可以在 else 循环中添加一个检查以仅检查数字,如下所示 -
function arrSum(arr) {
var sum = 0;
for (var i = 0; i < arr.length; i++) {
if (typeof arr[i] == 'object'){
sum += arrSum(arr[i]);
}else if (Number(arr[i])){
sum += arr[i];
}
}
return sum;
}
console.log(arrSum([2, 'a', 5, [4, 6, 10, [1, 2, 'b'], 10], 5]));
回答by Tomer W
I would build a function similar to what Pranav C Balanwith the difference that i would check the isObject()
before calling forEach()
,
This way i get around problems posed by sending a single numeric
parameter, or Null
values.
我会构建一个类似于Pranav C Balan的函数,不同之处在于我会isObject()
在调用之前检查它forEach()
,
这样我就可以解决发送单个numeric
参数或Null
值带来的问题。
function arrSum(v) {
// checking if element is an array
if (typeof v == 'object') {
var sum = 0;
// iterate array using forEach, better to use for loop since it have higher performance
v.forEach(function(e) {
sum+=arrSum(e);
});
return sum;
}
else {
return v;
}
}
$('body').append($('<p></p>').html('[2, 5, [4, 6], 5] = ' + arrSum([2, 5, [4, 6], 5])));
$('body').append($('<p></p>').html('[2,, 5] = ' + arrSum([2,, 5])));
$('body').append($('<p></p>').html('5 = ' + arrSum(5)));
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
回答by Penny Liu
This can be done with lodash _.flattenDeep
and _.sum
:
这可以通过 lodash_.flattenDeep
和_.sum
:
var arr = [2, 5, [4, 6], 5];
arrSum(arr);
function arrSum(arr) {
var arrFlattens = _.flattenDeep(arr);
// => [2, 5, 4, 6, 5]
console.log(_.sum(arrFlattens));
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>