如何使用 Android 通过 Request 发送 JSON 对象?

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时间:2020-08-20 08:21:43  来源:igfitidea点击:

How to send a JSON object over Request with Android?

androidjsonposthttprequest

提问by AndroidDev

I want to send the following JSON text

我想发送以下 JSON 文本

{"Email":"[email protected]","Password":"123456"}

to a web service and read the response. I know to how to read JSON. The problem is that the above JSON object must be sent in a variable name jason.

到 Web 服务并读取响应。我知道如何阅读 JSON。问题是上面的 JSON 对象必须以变量 name 发送jason

How can I do this from android? What are the steps such as creating request object, setting content headers, etc.

我怎么能从android做到这一点?创建请求对象、设置内容头等步骤有哪些?

采纳答案by dmazzoni

Android doesn't have special code for sending and receiving HTTP, you can use standard Java code. I'd recommend using the Apache HTTP client, which comes with Android. Here's a snippet of code I used to send an HTTP POST.

Android 没有发送和接收 HTTP 的特殊代码,您可以使用标准的 Java 代码。我建议使用 Android 附带的 Apache HTTP 客户端。这是我用来发送 HTTP POST 的一段代码。

I don't understand what sending the object in a variable named "jason" has to do with anything. If you're not sure what exactly the server wants, consider writing a test program to send various strings to the server until you know what format it needs to be in.

我不明白在名为“jason”的变量中发送对象与任何事情有什么关系。如果您不确定服务器到底想要什么,请考虑编写一个测试程序将各种字符串发送到服务器,直到您知道它需要采用什么格式。

int TIMEOUT_MILLISEC = 10000;  // = 10 seconds
String postMessage="{}"; //HERE_YOUR_POST_STRING.
HttpParams httpParams = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(httpParams, TIMEOUT_MILLISEC);
HttpConnectionParams.setSoTimeout(httpParams, TIMEOUT_MILLISEC);
HttpClient client = new DefaultHttpClient(httpParams);

HttpPost request = new HttpPost(serverUrl);
request.setEntity(new ByteArrayEntity(
    postMessage.toString().getBytes("UTF8")));
HttpResponse response = client.execute(request);

回答by Primal Pappachan

Sending a json object from Android is easy if you use Apache HTTP Client. Here's a code sample on how to do it. You should create a new thread for network activities so as not to lock up the UI thread.

如果您使用 Apache HTTP 客户端,从 Android 发送 json 对象很容易。这是有关如何执行此操作的代码示例。您应该为网络活动创建一个新线程,以免锁定 UI 线程。

    protected void sendJson(final String email, final String pwd) {
        Thread t = new Thread() {

            public void run() {
                Looper.prepare(); //For Preparing Message Pool for the child Thread
                HttpClient client = new DefaultHttpClient();
                HttpConnectionParams.setConnectionTimeout(client.getParams(), 10000); //Timeout Limit
                HttpResponse response;
                JSONObject json = new JSONObject();

                try {
                    HttpPost post = new HttpPost(URL);
                    json.put("email", email);
                    json.put("password", pwd);
                    StringEntity se = new StringEntity( json.toString());  
                    se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
                    post.setEntity(se);
                    response = client.execute(post);

                    /*Checking response */
                    if(response!=null){
                        InputStream in = response.getEntity().getContent(); //Get the data in the entity
                    }

                } catch(Exception e) {
                    e.printStackTrace();
                    createDialog("Error", "Cannot Estabilish Connection");
                }

                Looper.loop(); //Loop in the message queue
            }
        };

        t.start();      
    }

You could also use Google Gsonto send and retrieve JSON.

您还可以使用Google Gson发送和检索 JSON。

回答by Sachin Gurnani

public void postData(String url,JSONObject obj) {
    // Create a new HttpClient and Post Header

    HttpParams myParams = new BasicHttpParams();
    HttpConnectionParams.setConnectionTimeout(myParams, 10000);
    HttpConnectionParams.setSoTimeout(myParams, 10000);
    HttpClient httpclient = new DefaultHttpClient(myParams );
    String json=obj.toString();

    try {

        HttpPost httppost = new HttpPost(url.toString());
        httppost.setHeader("Content-type", "application/json");

        StringEntity se = new StringEntity(obj.toString()); 
        se.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));
        httppost.setEntity(se); 

        HttpResponse response = httpclient.execute(httppost);
        String temp = EntityUtils.toString(response.getEntity());
        Log.i("tag", temp);


    } catch (ClientProtocolException e) {

    } catch (IOException e) {
    }
}

回答by vikoo

HttpPostis deprecated by Android Api Level 22. So, Use HttpUrlConnectionfor further.

HttpPost已被 Android Api Level 22 弃用。因此,HttpUrlConnection进一步使用。

public static String makeRequest(String uri, String json) {
    HttpURLConnection urlConnection;
    String url;
    String data = json;
    String result = null;
    try {
        //Connect 
        urlConnection = (HttpURLConnection) ((new URL(uri).openConnection()));
        urlConnection.setDoOutput(true);
        urlConnection.setRequestProperty("Content-Type", "application/json");
        urlConnection.setRequestProperty("Accept", "application/json");
        urlConnection.setRequestMethod("POST");
        urlConnection.connect();

        //Write
        OutputStream outputStream = urlConnection.getOutputStream();
        BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(outputStream, "UTF-8"));
        writer.write(data);
        writer.close();
        outputStream.close();

        //Read
        BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(urlConnection.getInputStream(), "UTF-8"));

        String line = null;
        StringBuilder sb = new StringBuilder();

        while ((line = bufferedReader.readLine()) != null) {
            sb.append(line);
        }

        bufferedReader.close();
        result = sb.toString();

    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }
    return result;
}

回答by Alex

There's a surprisingly nice library for Android HTTP available at the link below:

在下面的链接中有一个非常好的 Android HTTP 库:

http://loopj.com/android-async-http/

http://loopj.com/android-async-http/

Simple requests are very easy:

简单的请求非常简单:

AsyncHttpClient client = new AsyncHttpClient();
client.get("http://www.google.com", new AsyncHttpResponseHandler() {
    @Override
    public void onSuccess(String response) {
        System.out.println(response);
    }
});

To send JSON (credit to `voidberg' at https://github.com/loopj/android-async-http/issues/125):

发送 JSON(归功于https://github.com/loopj/android-async-http/issues/125上的 `voidberg' ):

// params is a JSONObject
StringEntity se = null;
try {
    se = new StringEntity(params.toString());
} catch (UnsupportedEncodingException e) {
    // handle exceptions properly!
}
se.setContentType(new BasicHeader(HTTP.CONTENT_TYPE, "application/json"));

client.post(null, "www.example.com/objects", se, "application/json", responseHandler);

It's all asynchronous, works well with Android and safe to call from your UI thread. The responseHandler will run on the same thread you created it from (typically, your UI thread). It even has a built-in resonseHandler for JSON, but I prefer to use google gson.

这一切都是异步的,适用于 Android 并且可以安全地从您的 UI 线程调用。responseHandler 将在您创建它的同一个线程上运行(通常是您的 UI 线程)。它甚至有一个用于 JSON 的内置 resonseHandler,但我更喜欢使用 google gson。

回答by Sanjeet A

Now since the HttpClientis deprecated the current working code is to use the HttpUrlConnectionto create the connection and write the and read from the connection. But I preferred to use the Volley. This library is from android AOSP. I found very easy to use to make JsonObjectRequestor JsonArrayRequest

现在,由于HttpClient已弃用,当前的工作代码是使用HttpUrlConnection来创建连接并写入和读取连接。但我更喜欢使用Volley。这个库来自android AOSP。我发现制作JsonObjectRequest或使用非常容易JsonArrayRequest

回答by Dave Ranjan

Nothing could be simple than this. Use OkHttpLibrary

没有什么比这更简单的了。使用 OkHttpLibrary

Create your json

创建你的json

JSONObject requestObject = new JSONObject();
requestObject.put("Email", email);
requestObject.put("Password", password);

and send it like this.

并像这样发送。

OkHttpClient client = new OkHttpClient();

RequestBody body = RequestBody.create(JSON, json);
Request request = new Request.Builder()
            .addHeader("Content-Type","application/json")
            .url(url)
            .post(requestObject.toString())
            .build();

okhttp3.Response response = client.newCall(request).execute();

回答by Niral Dharmnathi

public class getUserProfile extends AsyncTask<Void, String, JSONArray> {
    JSONArray array;
    @Override
    protected JSONArray doInBackground(Void... params) {

        try {
            commonurl cu = new commonurl();
            String u = cu.geturl("tempshowusermain.php");
            URL url =new URL(u);
          //  URL url = new URL("http://192.168.225.35/jabber/tempshowusermain.php");
            HttpURLConnection httpURLConnection = (HttpURLConnection) url.openConnection();
            httpURLConnection.setRequestMethod("POST");
            httpURLConnection.setRequestProperty("Content-Type", "application/json");
            httpURLConnection.setRequestProperty("Accept", "application/json");
            httpURLConnection.setDoOutput(true);
            httpURLConnection.setRequestProperty("Connection", "Keep-Alive");
            httpURLConnection.setDoInput(true);
            httpURLConnection.connect();

            JSONObject jsonObject=new JSONObject();
            jsonObject.put("lid",lid);


            DataOutputStream outputStream = new DataOutputStream(httpURLConnection.getOutputStream());
            outputStream.write(jsonObject.toString().getBytes("UTF-8"));

            int code = httpURLConnection.getResponseCode();
            if (code == 200) {
                BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(httpURLConnection.getInputStream()));

                StringBuffer stringBuffer = new StringBuffer();
                String line;

                while ((line = bufferedReader.readLine()) != null) {
                    stringBuffer.append(line);
                }
                object =  new JSONObject(stringBuffer.toString());
             //   array = new JSONArray(stringBuffer.toString());
                array = object.getJSONArray("response");

            }

        } catch (Exception e) {

            e.printStackTrace();
        }
        return array;


    }

    @Override
    protected void onPreExecute() {
        super.onPreExecute();



    }

    @Override
    protected void onPostExecute(JSONArray array) {
        super.onPostExecute(array);
        try {
            for (int x = 0; x < array.length(); x++) {

                object = array.getJSONObject(x);
                ComonUserView commUserView=new ComonUserView();//  commonclass.setId(Integer.parseInt(jsonObject2.getString("pid").toString()));
                //pidArray.add(jsonObject2.getString("pid").toString());

                commUserView.setLid(object.get("lid").toString());
                commUserView.setUname(object.get("uname").toString());
                commUserView.setAboutme(object.get("aboutme").toString());
                commUserView.setHeight(object.get("height").toString());
                commUserView.setAge(object.get("age").toString());
                commUserView.setWeight(object.get("weight").toString());
                commUserView.setBodytype(object.get("bodytype").toString());
                commUserView.setRelationshipstatus(object.get("relationshipstatus").toString());
                commUserView.setImagepath(object.get("imagepath").toString());
                commUserView.setDistance(object.get("distance").toString());
                commUserView.setLookingfor(object.get("lookingfor").toString());
                commUserView.setStatus(object.get("status").toString());

                cm.add(commUserView);
            }
            custuserprof = new customadapterformainprofile(getActivity(),cm,Tab3.this);
          gridusername.setAdapter(custuserprof);
            //  listusername.setAdapter(custuserprof);
            } catch (Exception e) {

                e.printStackTrace();
        }
    }