xcode Objective C中的Sqlite数据库插入语句
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/9972091/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Sqlite Database Insert Statement in Objective C
提问by Hacer Akac
I try to insert only two integer variable to my sqlite database. I created a database which name is ups.sqlite, it has a one table (upssTable) and the table have two column. But when I open /Users/ds/Library/Application Support/iPhone Simulator/5.0/Applications/FCB4B455-4B7F-4C47-81B6-AC4121874596/SqliteDeneme.app/ups.sqlite there is no data in ups.sqlite. My code is here:
我尝试只向我的 sqlite 数据库插入两个整数变量。我创建了一个名为 ups.sqlite 的数据库，它有一个表 (upssTable)，该表有两列。但是当我打开 /Users/ds/Library/Application Support/iPhone Simulator/5.0/Applications/FCB4B455-4B7F-4C47-81B6-AC4121874596/SqliteDeneme.app/ups.sqlite 时，ups.sqlite 中没有数据。我的代码在这里：
- (IBAction)buttonClick:(id)sender {
NSFileManager *fileManager = [NSFileManager defaultManager];
NSError *error;
NSString *dbPath = [self getDBPath];
BOOL success = [fileManager fileExistsAtPath:dbPath];
if(!success) {
NSString *defaultDBPath = [[[NSBundle mainBundle] resourcePath] stringByAppendingPathComponent:@"ups.sqlite"];
success = [fileManager copyItemAtPath:defaultDBPath toPath:dbPath error:&error];
if (!success)
NSAssert1(0, @"Failed to create writable database file with message '%@'.", [error localizedDescription]);
}
NSLog(@"database path %@",dbPath);
if(!(sqlite3_open([dbPath UTF8String], &cruddb) == SQLITE_OK))
{
NSLog(@"An error has occured.");
}
if(sqlite3_open([dbPath UTF8String], &cruddb) ==SQLITE_OK){
NSString * str1 =@"1";
NSString * str2 =@"1";
const char *sql = "INSERT INTO upssTable (column1, column2) VALUES (?,?)";
NSInteger result = sqlite3_prepare_v2(cruddb,sql, -1, &stmt, NULL);
NSLog(@"upss %s\n", sqlite3_errmsg(cruddb));
if(result == SQLITE_OK)
{
sqlite3_bind_int(stmt, 1, [str1 integerValue]);
sqlite3_bind_int(stmt, 2, [str2 integerValue]);
}
else
{
NSAssert1(0, @"Error . '%s'", sqlite3_errmsg(cruddb));
}
sqlite3_reset(stmt);
sqlite3_finalize(stmt);
sqlite3_close(cruddb);
}
}
- (NSString *) getDBPath {
NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory , NSUserDomainMask, YES);
NSString *documentsDir = [paths objectAtIndex:0];
return [documentsDir stringByAppendingPathComponent:@"ups.sqlite"];
}
How can I solve this problem? Please help me. Thanks for your reply.
我怎么解决这个问题？请帮我。感谢您的回复。
回答by trojanfoe
You are creating your sqlite3 statement, but you aren't actually executing it using sqlite3_step().
您正在创建 sqlite3 语句，但实际上并没有使用sqlite3_step().
Also you appear to be opening the database twice?
您似乎还两次打开数据库？
回答by Akash Malhotra
You havent used sqlite3_step() at all. Try this way...
您根本没有使用过 sqlite3_step()。试试这个方法...
sqlite3 *database;
dbPath=[self.databasePath UTF8String];
if(sqlite3_open(dbPath,&database)==SQLITE_OK)
{
const char *sqlstatement = "INSERT INTO upssTable (column1, column2) VALUES (?,?)";
sqlite3_stmt *compiledstatement;
if(sqlite3_prepare_v2(database,sqlstatement , -1, &compiledstatement, NULL)==SQLITE_OK)
{
NSString * str1 =@"1";
NSString * str2 =@"1";
sqlite3_bind_int(compiledstatement, 1, [str1 integerValue]);
sqlite3_bind_int(compiledstatement, 2, [str2 integerValue]);
if(sqlite3_step(compiledstatement)==SQLITE_DONE)
{
NSLog(@"done");
}
else NSLog(@"ERROR");
sqlite3_reset(compiledstatement);
}
else
{
NSAssert1(0, @"Error . '%s'", sqlite3_errmsg(cruddb));
}
sqlite3_close(database);
}
