laravel 调用非对象上的成员函数 getClientOriginalExtension()
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Call to a member function getClientOriginalExtension() on a non-object
提问by Jensej
I'm trying to make an image uploader, but it always give me this error
我正在尝试制作图像上传器，但它总是给我这个错误
Call to a member function getClientOriginalName() on a non-object here is my code controller code
在非对象上调用成员函数 getClientOriginalName() 是我的代码控制器代码
public function postSubtitle()
{
//$video = Video::where('user_id', '=', Auth::id())->find(Input::all('id'));
var_dump(Input::all());
$file= Input::file('name');
echo $file->getClientOriginalExtension();
}
and here is the upload form
这是上传表格
{{ form_open({'url': 'video/subtitle', 'files': 'true'}) }}
{{ form_file('name', {class: 'form-control'} ) }}
{{ form_submit(trans('main.edit'), {class: 'btn btn-lg btn-success btn-block'}) }}
{{form_close()}}
what's wrong with my code?
我的代码有什么问题？
回答by Marwelln
If you want to handle file uploads, your formmust have enctype="multipart/form-data". (You might have that, but we don't know how your function form_openworks.)
如果你想处理文件上传，你form必须有enctype="multipart/form-data". （你可能有那个，但我们不知道你的函数是如何form_open工作的。）
If you have that but still get the same error it should mean that you haven't selected any file. If you don't upload a file, Input::file('name')will be nullinstead of an object.
如果你有那个但仍然得到同样的错误，这应该意味着你没有选择任何文件。如果你不上传文件，Input::file('name')将null代替一个对象。
So what you should do is to first check if it's not null, and then continue to handle your file.
所以你应该做的是首先检查它是否不为空，然后继续处理你的文件。
$file = Input::file('name');
if ($file !== null) {
echo $file->getClientOriginalExtension();
}
