asp.net-mvc 如何在 ASP.NET MVC 中创建文件并通过 FileResult 返回它？
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How to create file and return it via FileResult in ASP.NET MVC?
提问by Ante
I have to create and return file in my aplication ASP.net MVC aplication. The file type should be normal .txt file. I know that i can return FileResult but i don't know how to use it.
我必须在我的应用程序 ASP.net MVC 应用程序中创建并返回文件。文件类型应该是普通的 .txt 文件。我知道我可以返回 FileResult 但我不知道如何使用它。
public FilePathResult GetFile()
{
string name = "me.txt";
FileInfo info = new FileInfo(name);
if (!info.Exists)
{
using (StreamWriter writer = info.CreateText())
{
writer.WriteLine("Hello, I am a new text file");
}
}
return File(name, "text/plain");
}
This code doesn't work. Why? How to do it with stream result?
此代码不起作用。为什么？如何处理流结果？
回答by BigBlondeViking
EDIT ( If you want the stream try this: )
编辑（如果你想要流试试这个:)
public FileStreamResult GetFile()
{
string name = "me.txt";
FileInfo info = new FileInfo(name);
if (!info.Exists)
{
using (StreamWriter writer = info.CreateText())
{
writer.WriteLine("Hello, I am a new text file");
}
}
return File(info.OpenRead(), "text/plain");
}
You could try something like this..
你可以试试这样的..
public FilePathResult GetFile()
{
string name = "me.txt";
FileInfo info = new FileInfo(name);
if (!info.Exists)
{
using (StreamWriter writer = info.CreateText())
{
writer.WriteLine("Hello, I am a new text file");
}
}
return File(name, "text/plain");
}
回答by Tomas Aschan
Open the file to a StreamReader, and pass the stream as an argument to the FileResult:
打开文件到 a StreamReader，并将流作为参数传递给 FileResult：
public ActionResult GetFile()
{
var stream = new StreamReader("thefilepath.txt");
return File(stream.ReadToEnd(), "text/plain");
}
回答by Bronek
Another example of creating and downloading file from ASP NET MVC application at once but file content is created in memory (RAM) - on the fly:
另一个从 ASP NET MVC 应用程序同时创建和下载文件的示例，但文件内容是在内存 (RAM) 中创建的 - 即时：
public ActionResult GetTextFile()
{
UTF8Encoding encoding = new UTF8Encoding();
byte[] contentAsBytes = encoding.GetBytes("this is text content");
this.HttpContext.Response.ContentType = "text/plain";
this.HttpContext.Response.AddHeader("Content-Disposition", "filename=" + "text.txt");
this.HttpContext.Response.Buffer = true;
this.HttpContext.Response.Clear();
this.HttpContext.Response.OutputStream.Write(contentAsBytes, 0, contentAsBytes.Length);
this.HttpContext.Response.OutputStream.Flush();
this.HttpContext.Response.End();
return View();
}
