java 无法将字符串转换为 ZonedDateTime：DateTimeParseException
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Can't convert string to ZonedDateTime: DateTimeParseException
提问by Zi-yan Tseng
I try to convert string from JSON to ZonedDateTime just like
我尝试将字符串从 JSON 转换为 ZonedDateTime 就像
static String getWatchTime(JSONObject aJson, JSONObject bJson) {
long difference = 0 ;
try {
String aTime = aJson.getString("time_utc_8");
String bTime = bJson.getString("time_utc_8");
String pattern = "yyyy-MM-dd HH:mm:ss.SSSSSS";
DateTimeFormatter Parser = DateTimeFormatter.ofPattern(pattern).ISO_DATE;
System.out.println(aTime);
ZonedDateTime a = ZonedDateTime.parse(aTime, Parser);
ZonedDateTime b = ZonedDateTime.parse(bTime, Parser);
ChronoUnit unit = null;
difference = unit.between(a, b);
System.out.println(difference);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
String t = difference +"";
return t;
}
and always get the error
并且总是得到错误
Exception in thread "main" java.time.format.DateTimeParseException: Text '2016-06-28 22:29:44.700228' could not be parsed: Unable to obtain OffsetDateTime from TemporalAccessor: {},ISO resolved to 2016-06-28T22:29:44.700228 of type java.time.format.Parsed
at java.time.format.DateTimeFormatter.createError(Unknown Source)
at java.time.format.DateTimeFormatter.parse(Unknown Source)
at java.time.OffsetDateTime.parse(Unknown Source)
at Q2.getWatchTime(Q2.java:321)
at Q2.WatchTime(Q2.java:265)
at Q2.main(Q2.java:31)
I want to get the difference between these two date.
I've tried SimpleDateFormatbut it will get the error result, for the mills.
我想知道这两个日期之间的差异。我试过，SimpleDateFormat但它会得到错误结果，对于工厂。
回答by Ole V.V.
I think it's already all in the comments, so this is just to sum up.
我想这已经全部在评论中了，所以这只是总结一下。
(1) Your format pattern string is correct. You just need to delete .ISO_DATEfrom the following line, so it becomes:
(1) 您的格式模式字符串是正确的。您只需.ISO_DATE要从以下行中删除，就变成了：
DateTimeFormatter Parser = DateTimeFormatter.ofPattern(pattern);
(ISO_DATEaccepts for example '2011-12-03+01:00' or '2011-12-03', a date without time with or without an offset from UTC; you've got nothing to use it for here as far as I can tell.)
（ISO_DATE例如接受'2011-12-03+01:00'或'2011-12-03'，一个没有时间的日期，有或没有UTC的偏移量；就我而言，你在这里没有什么可使用的可以说。）
(2) Since your string seems to have neither time zone nor offset, use LocalDateTime:
(2) 由于您的字符串似乎既没有时区也没有偏移量，请使用LocalDateTime：
LocalDateTime a = LocalDateTime.parse(aTime, Parser);
LocalDateTime b = LocalDateTime.parse(bTime, Parser);
If you need to take summer time (DST) or the like into account when calculating the difference, convert the time after parsing:
如果在计算差异时需要考虑夏令时（DST）等，则解析后转换时间：
ZoneId timeZone = ZoneId.systemDefault();
ZonedDateTime a = LocalDateTime.parse(aTime, Parser).atZone(timeZone);
ZonedDateTime b = LocalDateTime.parse(bTime, Parser).atZone(timeZone);
Please think twice about the time zone to use for conversion so you are sure to get the expected result.
请仔细考虑用于转换的时区，以便您确保获得预期的结果。
(3) A ChronoUnitof nullwon't work. I don't know which one you intended, so this option is picked rather at random:
（3）ChronoUnit的null将无法工作。我不知道你想要哪个，所以这个选项是随机选择的：
ChronoUnit unit = ChronoUnit.DAYS;
With these three changes your method executes nicely on my computer. In one run it printed:
通过这三个更改，您的方法可以在我的计算机上很好地执行。在一次运行中，它打印出：
2016-06-28 22:29:44.700228
365
In the same run it returned a string of 365.
在同一次运行中，它返回了一串365.
回答by Zi-yan Tseng
i get the answer by Andreas(in comment) i used this code to achieve my goal finally
我得到了 Andreas 的答案（在评论中）我最终使用此代码实现了我的目标
static String getWatchTime(JSONObject aJson, JSONObject bJson) {
double difference = 0 ;
try {
String aTime = aJson.getString("time_utc_8");
String bTime = bJson.getString("time_utc_8");
String pattern = "yyyy-MM-dd HH:mm:ss.SSSSSS";
DateTimeFormatter Parser = DateTimeFormatter.ofPattern(pattern).withZone(ZoneId.systemDefault());
System.out.println(aTime);
ZonedDateTime a = ZonedDateTime.parse(aTime,Parser);
ZonedDateTime b = ZonedDateTime.parse(bTime,Parser);
System.out.println(a);
System.out.println(b);
//ChronoUnit unit = null ;
difference = ChronoUnit.MICROS.between(a, b);
} catch (JSONException e) {
e.printStackTrace();
} /*catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}*/
String t = difference +"";
return t;
}
I didn't set the TimeZone, so can't convert the input as string to ZonedDateTime.
And I need to get the microssecond , hence i use ChronoUnit.MICROS.between()Thanks for answers
我没有设置时区，所以不能将输入作为字符串转换为 ZonedDateTime。我需要获得微秒，因此我使用ChronoUnit.MICROS.between()感谢您的回答
